Steply

x = t^2, y = t^3, find dy/dx

Step by step, with the reason for every step · Parametric curves · Calculus 2

Step by step

The question

Question: find dy/dx, when x = t² and y = t³.

x = t2
y = t3

1 dx/dt and dy/dt

The power rule, with t: dx/dt = 2t.

dxdt = 2t

And dy/dt = 3t².

dydt = 3t2

2 dy/dx

The slope dy over dx is dy over dt, divided by dx over dt: the dt's cancel.

dydx = dydtdxdt

So dy/dx is 3t² over (2t).

dydx = 3t22t

Simplify: divide the numbers, take away the powers of t.

= 32t

Careful!

dy goes on top: dy over dt, divided by dx over dt.

Not the other way round.

Careful: not dx/dtdy/dt ✗

So dy/dx = 3/2 × t.

dydx = 32t

3 Check

Let's check with a calculator: move t a tiny bit around 1, and divide the change in y by the change in x.

About 1.5: the slope 1.5 our rule gives.

Right!

t = 1 ± 0.001: ΔyΔx ≈ 1.5

Let's look back.

First: dx/dt and dy/dt.

Then: dy/dx.

Last: check.

Answer
dydx = 32t

Your turn

Try this one yourself, then check:

Find dy/dx, when x = 3t2
Show the answer
12t

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