Step by step
The question
Question: find dy/dx, when x = t² and y = t³.
x = t2
y = t3
1 dx/dt and dy/dt
The power rule, with t: dx/dt = 2t.
dxdt = 2t
And dy/dt = 3t².
dydt = 3t2
2 dy/dx
The slope dy over dx is dy over dt, divided by dx over dt: the dt's cancel.
dydx = dydtdxdt
So dy/dx is 3t² over (2t).
dydx = 3t22t
Simplify: divide the numbers, take away the powers of t.
= 32t
Careful!
dy goes on top: dy over dt, divided by dx over dt.
Not the other way round.
Careful: not dx/dtdy/dt ✗
So dy/dx = 3/2 × t.
dydx = 32t
3 Check
Let's check with a calculator: move t a tiny bit around 1, and divide the change in y by the change in x.
About 1.5: the slope 1.5 our rule gives.
Right!
t = 1 ± 0.001: ΔyΔx ≈ 1.5
Let's look back.
First: dx/dt and dy/dt.
Then: dy/dx.
Last: check.
Answer
dydx = 32t