Steply

Xy = 6, find the slope at (2, 3)

Step by step, with the reason for every step · Implicit differentiation · Calculus

Step by step

The question

Question: find the slope of xy = 6 at the point (2, 3).

xy = 6

y is not written alone, but y still depends on x.

So for y we use the chain rule.

y squared gives 2y, times dy/dx.

y depends on x: y2 → 2y × dydx

1 The derivative of each side

xy is x times y: use the product rule.

The derivative of x is 1, and of y is dy/dx.

(uv)′ = u′v + uv′
xy → y + x dydx

Now each term.

x terms as usual, y terms times dy/dx, a number alone gives 0.

y + x dydx = 0

2 Get dy/dx alone

Keep the dy/dx terms on the left.

Move the others to the right: they change sign.

x dydx = −y

To remove times x, we divide both sides by it.

dydx = −yx

Tidy up: dy/dx = −y over x.

dydx = −yx

3 The slope at the point

First, is (2, 3) on the curve?

Put x = 2 and y = 3 in.

We get 6.

Yes, it is.

(2)(3) = 6 ✓

Put x = 2 and y = 3 into dy/dx.

So the slope at (2, 3) is −3/2.

dydx = −32

4 Check

Let's check with a very close point on the curve.

At x = 2.001, a calculator gives y ≈ 2.9985.

x = 2.001: y ≈ 2.9985

The slope between the two points: down 0.0015, across 0.001.

About −1.5.

Very close to −1.5.

Right!

2.9985 − 30.001 ≈ −1.5

Let's look back.

First: the derivative of each side.

Then: get dy/dx alone.

Then: the slope at the point.

Last: check.

Answer
dydx = −yx

Your turn

Try this one yourself, then check:

Find the slope of xy = 12
Show the answer
slope = −43

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