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y varies directly with the square of x. y = 12 when x = 2. Find y…

Step by step, with the reason for every step · Direct and inverse variation · Algebra 1

Step by step

The question

Question: y varies directly with the square of x.

y = 12 when x = 2.

Find y when x = 5.

1 Write the rule

Varies directly means y is always the same number times x².

When x gets bigger, y gets bigger too.

We call the number k: y = kx².

y = kx2

k stays the same for every pair of numbers.

Books call it the constant of variation.

k stays the same

2 Find k

We put in y = 12 and x = 2.

2 squared is 4, and k times 4 is written 4k.

12 = 4k
2² = 2 × 2 = 4

4k means 4 times k.

We want just k.

To remove times 4, we divide by 4.

We do it on both sides, so they stay equal.

Careful!

k is y divided by x²: 12/4.

Not 4/12.

The y number goes on top.

Careful: not k = 412 ✗

12/4 on the left.

4k/4 on the right.

124 = 4k4

4 divided by 4 is 1.

So just k is left.

12 divided by 4 is 3.

124 = 3

So k = 3.

k = 3

3 Write the equation

We put 3 in place of k.

So the equation is y = 3x².

y = 3x2

4 Find y

We put in x = 5.

y = 3 × 52

5 squared is 25.

5² = 25

3 times 25 is 75.

3 × 25 = 75

So y = 75.

y = 75

5 Check

Let's check.

In direct variation, y divided by x² is always k.

First pair: 12/4 is 3.

y ÷ x²: 124 = 3

New pair: 75/25 is 3 too.

The same k.

So the answer is right!

7525 = 3

Let's look back.

First: write the rule.

Then: find k.

Then: write the equation.

Then: find y.

Last: check.

Answer
y = 75

Your turn

Try this one yourself, then check:

Show the answer
y = 64

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