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Find k

A system with no / infinitely many solutions · Algebra 1 · 20 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Make the x parts the same
  2. Compare ③ and ②
  3. Find k
  4. Check

The steps for 2x + 3y = 6 and 4x + ky = 5 have no solution. Find k.. Every solution names its steps, so you always know what comes next.

Worked examples

2x + 3y = 6 and 4x + ky = 5 have no solution. Find k. Easy

The question

Question: for which k do 2x + 3y = 6 and 4x + ky = 5 have no solution?

2x + 3y = 6①

We call them ① and ②.

No solution means no point (x, y) works for both.

4x + ky = 5②we want: no solution

1 Make the x parts the same

To compare the equations, we make the parts of one letter the same.

k is with y, so we use the other letter, x: it has plain numbers in front.

The x parts: 2x in ① and 4x in ②.

4 divided by 2 is 2.

So 2x times 2 is 4x.

4 ÷ 2 = 2

We multiply every part of ① by 2.

We do it on both sides, so they stay equal.

2 × 2x + 2 × 3y = 2 × 6① × 2

2 times 2x is 4x.

2 times 3y is 6y.

2 times 6 is 12.

We call it ③.

4x + 6y = 12③

2 Compare ③ and ②

We write ② again, under ③.

4x + ky = 5②

If the left sides are the same, both equations talk about the same amount, 4x + 6y.

One amount cannot be 12 and 5 at once.

So no point works: no solution.

same left side, different numbers → no solution

If the numbers are the same too, it is one equation written twice.

Every point on that line works: infinitely many solutions.

same left side, same number → infinitely many

If the left sides are different, we can take one equation away from the other.

Some y is left, so we can find y.

That gives one solution.

different left sides → one solution

Careful!

We compare with ③, not ①.

① was times 2.

3y times 2 is 6y.

Careful: not k = 3 ✗

3 Find k

We want no solution.

So the left sides must be the same: ky = 6y.

ky = 6y

k times y is 6 times y when k is 6.

So k = 6.

k = 6

And the numbers, 12 and 5, are different.

Good.

numbers: 12 and 5, different ✓

4 Check

Let's check.

We put k = 6 into ②.

4x + 6y = 5②

Take ② away from ③.

The left sides are the same, so together they make 0.

The numbers: 12 take away 5.

③ − ②: (4x + 6y) − (4x + 6y) = 12 − 5

0 = 7 is never true.

So there is no solution.

It works!

0 = 7 never true

On a grid, the two lines look like this.

Same x and y parts means the same slope.

So the lines are parallel.

Parallel lines never meet: no solution.

Let's look back.

First: make the x parts the same.

Then: compare ③ and ②.

Then: find k.

Last: check.

Answer
numbers: 12 and 5, different ✓

▶ Watch it solved

2x + 5y = 3 and 6x + ky = 9 have infinitely many solutions. Find k. Medium

The question

Question: for which k do 2x + 5y = 3 and 6x + ky = 9 have infinitely many solutions?

2x + 5y = 3①

We call them ① and ②.

Infinitely many solutions means every point on a line works for both.

6x + ky = 9②we want: infinitely many solutions

1 Make the x parts the same

To compare the equations, we make the parts of one letter the same.

k is with y, so we use the other letter, x: it has plain numbers in front.

The x parts: 2x in ① and 6x in ②.

6 divided by 2 is 3.

So 2x times 3 is 6x.

6 ÷ 2 = 3

We multiply every part of ① by 3.

We do it on both sides, so they stay equal.

3 × 2x + 3 × 5y = 3 × 3① × 3

3 times 2x is 6x.

3 times 5y is 15y.

3 times 3 is 9.

We call it ③.

6x + 15y = 9③

2 Compare ③ and ②

We write ② again, under ③.

6x + ky = 9②

If the left sides are the same, both equations talk about the same amount, 6x + 15y.

One amount cannot be two different numbers at once.

So no point works: no solution.

same left side, different numbers → no solution

If the numbers are the same too, it is one equation written twice.

Every point on that line works: infinitely many solutions.

same left side, same number → infinitely many

If the left sides are different, we can take one equation away from the other.

Some y is left, so we can find y.

That gives one solution.

different left sides → one solution

Careful!

We compare with ③, not ①.

① was times 3.

5y times 3 is 15y.

Careful: not k = 5 ✗

3 Find k

We want infinitely many solutions.

So the left sides must be the same: ky = 15y.

ky = 15y

k times y is 15 times y when k is 15.

So k = 15.

k = 15

And the numbers, 9 and 9, are the same too.

Good.

numbers: 9 and 9, the same ✓

4 Check

Let's check.

We put k = 15 into ②.

6x + 15y = 9②

Take ② away from ③.

The left sides are the same, so together they make 0.

The numbers: 9 take away 9.

③ − ②: (6x + 15y) − (6x + 15y) = 9 − 9

0 = 0 is always true.

They are the same equation.

It works!

0 = 0 always true

On a grid, both equations give the same line.

② lies right on top of ①.

Every point on the line works for both: infinitely many solutions.

Let's look back.

First: make the x parts the same.

Then: compare ③ and ②.

Then: find k.

Last: check.

Answer
numbers: 9 and 9, the same ✓

▶ Watch it solved

Kx - 4y = 6 and 3x - 2y = 1 have no solution. Find k. Harder

The question

Question: for which k do kx − 4y = 6 and 3x − 2y = 1 have no solution?

kx − 4y = 6①

We call them ① and ②.

No solution means no point (x, y) works for both.

3x − 2y = 1②we want: no solution

1 Make the y parts the same

To compare the equations, we make the parts of one letter the same.

k is with x, so we use the other letter, y: it has plain numbers in front.

The y parts: −2y in ② and −4y in ①.

−4 divided by −2 is 2.

So −2y times 2 is −4y.

−4 ÷ (−2) = 2

We multiply every part of ② by 2.

We do it on both sides, so they stay equal.

2 × 3x + 2 × (−2y) = 2 × 1② × 2

2 times 3x is 6x.

2 times −2y is −4y.

2 times 1 is 2.

We call it ③.

6x − 4y = 2③

2 Compare ③ and ①

We write ① again, under ③.

kx − 4y = 6①

If the left sides are the same, both equations talk about the same amount, 6x − 4y.

One amount cannot be 2 and 6 at once.

So no point works: no solution.

same left side, different numbers → no solution

If the numbers are the same too, it is one equation written twice.

Every point on that line works: infinitely many solutions.

same left side, same number → infinitely many

If the left sides are different, we can take one equation away from the other.

Some x is left, so we can find x.

That gives one solution.

different left sides → one solution

Careful!

We compare with ③, not ②.

② was times 2.

3x times 2 is 6x.

Careful: not k = 3 ✗

3 Find k

We want no solution.

So the left sides must be the same: kx = 6x.

kx = 6x

k times x is 6 times x when k is 6.

So k = 6.

k = 6

And the numbers, 2 and 6, are different.

Good.

numbers: 2 and 6, different ✓

4 Check

Let's check.

We put k = 6 into ①.

6x − 4y = 6①

Take ① away from ③.

The left sides are the same, so together they make 0.

The numbers: 2 take away 6.

③ − ①: (6x − 4y) − (6x − 4y) = 2 − 6

0 = −4 is never true.

So there is no solution.

It works!

0 = −4 never true

On a grid, the two lines look like this.

Same x and y parts means the same slope.

So the lines are parallel.

Parallel lines never meet: no solution.

Let's look back.

First: make the y parts the same.

Then: compare ③ and ①.

Then: find k.

Last: check.

Answer
numbers: 2 and 6, different ✓

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. 2x + 3y = 6 and 4x + ky = 5 have no solution. Find k.
    Answer
    numbers: 12 and 5, different ✓
  2. x + 2y = 5 and 3x + ky = 15 have infinitely many solutions. Find k.
    Answer
    numbers: 15 and 15, the same ✓
  3. x + y = 4 and 2x + ky = 3 have no solution. Find k.
    Answer
    numbers: 8 and 3, different ✓
  4. x - 2y = 4 and 3x - 6y = k have infinitely many solutions. Find k.
    Answer
    k = 12
  5. x + 3y = 2 and 2x + 6y = k have infinitely many solutions. Find k.
    Answer
    k = 4
  6. 3x + y = 5 and 6x + ky = 1 have no solution. Find k.
    Answer
    numbers: 10 and 1, different ✓
  7. x + y = 7 and x + ky = 2 have no solution. Find k.
    Answer
    numbers: 7 and 2, different ✓
  8. x - y = 3 and 4x - 4y = k have no solution. Find k.
    Answer
    k ≠ 12

Medium

  1. 2x + 5y = 3 and 6x + ky = 9 have infinitely many solutions. Find k.
    Answer
    numbers: 9 and 9, the same ✓
  2. kx + 6y = 4 and 2x + 3y = 5 have no solution. Find k.
    Answer
    numbers: 10 and 4, different ✓
  3. 2x - 3y = 1 and -4x + ky = 7 have no solution. Find k.
    Answer
    numbers: −2 and 7, different ✓
  4. 3x + 2y = 8 and 9x + ky = 24 have infinitely many solutions. Find k.
    Answer
    numbers: 24 and 24, the same ✓
  5. 4x - y = 2 and 8x + ky = 3 have no solution. Find k.
    Answer
    numbers: 4 and 3, different ✓
  6. 5x + 2y = 10 and 10x + 4y = k have no solution. Find k.
    Answer
    k ≠ 20
  7. x + 4y = -2 and 3x + ky = -6 have infinitely many solutions. Find k.
    Answer
    numbers: −6 and −6, the same ✓
  8. For which k do 2x + y = 3 and 6x + ky = 9 have infinitely many solutions?
    Answer
    numbers: 9 and 9, the same ✓

Harder

  1. kx - 4y = 6 and 3x - 2y = 1 have no solution. Find k.
    Answer
    numbers: 2 and 6, different ✓
  2. 2x + 3y = 0 and 6x + ky = 0 have infinitely many solutions. Find k.
    Answer
    numbers: 0 and 0, the same ✓
  3. 3x - 5y = 2 and -6x + ky = -4 have infinitely many solutions. Find k.
    Answer
    numbers: −4 and −4, the same ✓
  4. a + 2b = 3 and 4a + kb = 1 have no solution. Find k.
    Answer
    numbers: 12 and 1, different ✓