Worked examples
The question
Question: for which k do 2x + 3y = 6 and 4x + ky = 5 have no solution?
2x + 3y = 6①
We call them ① and ②.
No solution means no point (x, y) works for both.
4x + ky = 5②we want: no solution
1 Make the x parts the same
To compare the equations, we make the parts of one letter the same.
k is with y, so we use the other letter, x: it has plain numbers in front.
The x parts: 2x in ① and 4x in ②.
4 divided by 2 is 2.
So 2x times 2 is 4x.
4 ÷ 2 = 2
We multiply every part of ① by 2.
We do it on both sides, so they stay equal.
2 × 2x + 2 × 3y = 2 × 6① × 2
2 times 2x is 4x.
2 times 3y is 6y.
2 times 6 is 12.
We call it ③.
4x + 6y = 12③
2 Compare ③ and ②
We write ② again, under ③.
4x + ky = 5②
If the left sides are the same, both equations talk about the same amount, 4x + 6y.
One amount cannot be 12 and 5 at once.
So no point works: no solution.
same left side, different numbers → no solution
If the numbers are the same too, it is one equation written twice.
Every point on that line works: infinitely many solutions.
same left side, same number → infinitely many
If the left sides are different, we can take one equation away from the other.
Some y is left, so we can find y.
That gives one solution.
different left sides → one solution
Careful!
We compare with ③, not ①.
① was times 2.
3y times 2 is 6y.
Careful: not k = 3 ✗
3 Find k
We want no solution.
So the left sides must be the same: ky = 6y.
ky = 6y
k times y is 6 times y when k is 6.
So k = 6.
k = 6
And the numbers, 12 and 5, are different.
Good.
numbers: 12 and 5, different ✓
4 Check
Let's check.
We put k = 6 into ②.
4x + 6y = 5②
Take ② away from ③.
The left sides are the same, so together they make 0.
The numbers: 12 take away 5.
③ − ②: (4x + 6y) − (4x + 6y) = 12 − 5
0 = 7 is never true.
So there is no solution.
It works!
0 = 7 never true
On a grid, the two lines look like this.
Same x and y parts means the same slope.
So the lines are parallel.
Parallel lines never meet: no solution.
Let's look back.
First: make the x parts the same.
Then: compare ③ and ②.
Then: find k.
Last: check.
Answer numbers: 12 and 5, different ✓
▶ Watch it solved
The question
Question: for which k do 2x + 5y = 3 and 6x + ky = 9 have infinitely many solutions?
2x + 5y = 3①
We call them ① and ②.
Infinitely many solutions means every point on a line works for both.
6x + ky = 9②we want: infinitely many solutions
1 Make the x parts the same
To compare the equations, we make the parts of one letter the same.
k is with y, so we use the other letter, x: it has plain numbers in front.
The x parts: 2x in ① and 6x in ②.
6 divided by 2 is 3.
So 2x times 3 is 6x.
6 ÷ 2 = 3
We multiply every part of ① by 3.
We do it on both sides, so they stay equal.
3 × 2x + 3 × 5y = 3 × 3① × 3
3 times 2x is 6x.
3 times 5y is 15y.
3 times 3 is 9.
We call it ③.
6x + 15y = 9③
2 Compare ③ and ②
We write ② again, under ③.
6x + ky = 9②
If the left sides are the same, both equations talk about the same amount, 6x + 15y.
One amount cannot be two different numbers at once.
So no point works: no solution.
same left side, different numbers → no solution
If the numbers are the same too, it is one equation written twice.
Every point on that line works: infinitely many solutions.
same left side, same number → infinitely many
If the left sides are different, we can take one equation away from the other.
Some y is left, so we can find y.
That gives one solution.
different left sides → one solution
Careful!
We compare with ③, not ①.
① was times 3.
5y times 3 is 15y.
Careful: not k = 5 ✗
3 Find k
We want infinitely many solutions.
So the left sides must be the same: ky = 15y.
ky = 15y
k times y is 15 times y when k is 15.
So k = 15.
k = 15
And the numbers, 9 and 9, are the same too.
Good.
numbers: 9 and 9, the same ✓
4 Check
Let's check.
We put k = 15 into ②.
6x + 15y = 9②
Take ② away from ③.
The left sides are the same, so together they make 0.
The numbers: 9 take away 9.
③ − ②: (6x + 15y) − (6x + 15y) = 9 − 9
0 = 0 is always true.
They are the same equation.
It works!
0 = 0 always true
On a grid, both equations give the same line.
② lies right on top of ①.
Every point on the line works for both: infinitely many solutions.
Let's look back.
First: make the x parts the same.
Then: compare ③ and ②.
Then: find k.
Last: check.
Answer numbers: 9 and 9, the same ✓
▶ Watch it solved
The question
Question: for which k do kx − 4y = 6 and 3x − 2y = 1 have no solution?
kx − 4y = 6①
We call them ① and ②.
No solution means no point (x, y) works for both.
3x − 2y = 1②we want: no solution
1 Make the y parts the same
To compare the equations, we make the parts of one letter the same.
k is with x, so we use the other letter, y: it has plain numbers in front.
The y parts: −2y in ② and −4y in ①.
−4 divided by −2 is 2.
So −2y times 2 is −4y.
−4 ÷ (−2) = 2
We multiply every part of ② by 2.
We do it on both sides, so they stay equal.
2 × 3x + 2 × (−2y) = 2 × 1② × 2
2 times 3x is 6x.
2 times −2y is −4y.
2 times 1 is 2.
We call it ③.
6x − 4y = 2③
2 Compare ③ and ①
We write ① again, under ③.
kx − 4y = 6①
If the left sides are the same, both equations talk about the same amount, 6x − 4y.
One amount cannot be 2 and 6 at once.
So no point works: no solution.
same left side, different numbers → no solution
If the numbers are the same too, it is one equation written twice.
Every point on that line works: infinitely many solutions.
same left side, same number → infinitely many
If the left sides are different, we can take one equation away from the other.
Some x is left, so we can find x.
That gives one solution.
different left sides → one solution
Careful!
We compare with ③, not ②.
② was times 2.
3x times 2 is 6x.
Careful: not k = 3 ✗
3 Find k
We want no solution.
So the left sides must be the same: kx = 6x.
kx = 6x
k times x is 6 times x when k is 6.
So k = 6.
k = 6
And the numbers, 2 and 6, are different.
Good.
numbers: 2 and 6, different ✓
4 Check
Let's check.
We put k = 6 into ①.
6x − 4y = 6①
Take ① away from ③.
The left sides are the same, so together they make 0.
The numbers: 2 take away 6.
③ − ①: (6x − 4y) − (6x − 4y) = 2 − 6
0 = −4 is never true.
So there is no solution.
It works!
0 = −4 never true
On a grid, the two lines look like this.
Same x and y parts means the same slope.
So the lines are parallel.
Parallel lines never meet: no solution.
Let's look back.
First: make the y parts the same.
Then: compare ③ and ①.
Then: find k.
Last: check.
Answer numbers: 2 and 6, different ✓
▶ Watch it solved