Worked examples
The question
Question: solve x + y โ z = 0, x โ y + 3z = 8 and x โ y โ z = โ4.
x + y โ z = 0โ
x โ y + 3z = 8โก
We call them โ , โก and โข.
We want the x, y and z that make all three true.
x โ y โ z = โ4โข
The plan: remove one letter twice.
Then we have two equations with two letters, and we know how to solve those.
1 Remove y from โ and โก
Look at y in โ and โก: y and โy.
They are opposites, so adding removes y.
We write โ and โก under each other: x under x, y under y, z under z.
x + y โ z = 0โ
x โ y + 3z = 8โก
y and โy make zero.
Cross them out.
We add: the x parts, the z parts, and the numbers.
x + x = 2x.
โz + 3z = 2z.
0 + 8 = 8.
x + x = 2x
โz + 3z = 2z
0 + 8 = 8
Careful!
We add every part of both equations: each letter, and the numbers on the right too.
Careful: add every part, the numbers too
Now we have 2x + 2z = 8.
We call it โฃ.
It has no y.
2x + 2z = 8โฃ
2 Remove y from โ and โข
Look at y in โ and โข: y and โy.
They are opposites, so adding removes y.
We write โ and โข under each other: x under x, y under y, z under z.
x + y โ z = 0โ
x โ y โ z = โ4โข
y and โy make zero.
Cross them out.
We add: the x parts, the z parts, and the numbers.
x + x = 2x.
โz โ z = โ2z.
0 + (โ4) = โ4.
x + x = 2x
โz โ z = โ2z
0 + (โ4) = โ4
Now we have 2x โ 2z = โ4.
We call it โค.
It has no y.
2x โ 2z = โ4โค
Now โฃ and โค are two equations with two letters: x and z.
We solve them like before, by elimination.
We write โฃ and โค again, in columns.
2x + 2z = 8โฃ
2x โ 2z = โ4โค
3 Add the equations
Look at z: 2z and โ2z.
They are opposites.
Added, they make zero.
2z and โ2z make zero.
Cross them out.
We add โฃ and โค: the x parts together, and the numbers together.
2x + 2x = 4x.
8 + (โ4) = 4.
2x + 2x = 4x
8 + (โ4) = 4
Now we have 4x = 4.
4x = 4
4 Find x
4x means 4 times x.
We want just x.
To remove times 4, we divide by 4.
We do it on both sides, so they stay equal.
4x4 = 44
4 divided by 4 is 1.
So just x is left.
On the right too: 4 divided by 4 is 1.
44 = 1
So x = 1.
x = 1
5 Find z
We put x = 1 into โฃ.
2 times 1 is 2.
2(1) + 2z = 8
Now we have 2 + 2z = 8.
2 + 2z = 8
We want z by itself.
The 2 is in the way.
To remove 2, we take away 2.
We do it on both sides, so they stay equal.
2 + 2z โ 2 = 8 โ 2
2 and โ 2 make zero.
Cross them out.
8 minus 2 is 6.
8 โ 2 = 6
Now we have 2z = 6.
2z = 6
2z means 2 times z.
We want just z.
To remove times 2, we divide by 2.
We do it on both sides, so they stay equal.
2z2 = 62
2 divided by 2 is 1.
So just z is left.
6 divided by 2 is 3.
62 = 3
So z = 3.
z = 3
6 Find y
We put x = 1 and z = 3 into โ , the easiest one.
1 โ 3 + y = 0
1 โ 3 is โ2.
โ2 + y = 0
We want y by itself.
The โ2 is in the way.
To remove โ2, we add 2.
We do it on both sides, so they stay equal.
โ2 + y + 2 = 0 + 2
โ2 and + 2 make zero.
Cross them out.
0 plus 2 is 2.
0 + 2 = 2
So y = 2.
y = 2
So x = 1, y = 2 and z = 3, all at the same time.
We write it as (1, 2, 3).
(x, y, z) = (1, 2, 3)
7 Check
Let's check in every equation.
We put x = 1, y = 2, z = 3 into โ .
โ 1 + 2 โ 3 = 0
We get 0, the same as the right side.
Now โก.
โก 1 โ 2 + 3(3) = 1 โ 2 + 9 = 8
We get 8, the same as the right side.
Now โข.
โข 1 โ 2 โ 3 = โ4
We get โ4, the same as the right side.
All of them work.
So the answer is right!
Let's look back.
First: remove y from โ and โก.
Then: remove y from โ and โข.
Then: add the equations.
Then: find x.
Then: find z.
Then: find y.
Last: check.
Answer (x, y, z) = (1, 2, 3)
โถ Watch it solved
The question
Question: solve 2x + 3y + z = โ1, x โ y โ z = 3 and x โ y + z = 5.
2x + 3y + z = โ1โ
x โ y โ z = 3โก
We call them โ , โก and โข.
We want the x, y and z that make all three true.
x โ y + z = 5โข
The plan: remove one letter twice.
Then we have two equations with two letters, and we know how to solve those.
1 Remove z from โ and โก
Look at z in โ and โก: z and โz.
They are opposites, so adding removes z.
We write โ and โก under each other: x under x, y under y, z under z.
2x + 3y + z = โ1โ
x โ y โ z = 3โก
z and โz make zero.
Cross them out.
We add: the x parts, the y parts, and the numbers.
2x + x = 3x.
3y โ y = 2y.
โ1 + 3 = 2.
2x + x = 3x
3y โ y = 2y
โ1 + 3 = 2
Careful!
We add every part of both equations: each letter, and the numbers on the right too.
Careful: add every part, the numbers too
Now we have 3x + 2y = 2.
We call it โฃ.
It has no z.
3x + 2y = 2โฃ
2 Remove z from โก and โข
Look at z in โก and โข: โz and z.
They are opposites, so adding removes z.
We write โก and โข under each other: x under x, y under y, z under z.
x โ y โ z = 3โก
x โ y + z = 5โข
โz and z make zero.
Cross them out.
We add: the x parts, the y parts, and the numbers.
x + x = 2x.
โy โ y = โ2y.
3 + 5 = 8.
x + x = 2x
โy โ y = โ2y
3 + 5 = 8
Now we have 2x โ 2y = 8.
We call it โค.
It has no z.
2x โ 2y = 8โค
Now โฃ and โค are two equations with two letters: x and y.
We solve them like before, by elimination.
We write โฃ and โค again, in columns.
3x + 2y = 2โฃ
2x โ 2y = 8โค
3 Add the equations
Look at y: 2y and โ2y.
They are opposites.
Added, they make zero.
2y and โ2y make zero.
Cross them out.
We add โฃ and โค: the x parts together, and the numbers together.
3x + 2x = 5x.
2 + 8 = 10.
3x + 2x = 5x
2 + 8 = 10
Now we have 5x = 10.
5x = 10
4 Find x
5x means 5 times x.
We want just x.
To remove times 5, we divide by 5.
We do it on both sides, so they stay equal.
5x5 = 105
5 divided by 5 is 1.
So just x is left.
10 divided by 5 is 2.
105 = 2
So x = 2.
x = 2
5 Find y
We put x = 2 into โฃ.
3 times 2 is 6.
3(2) + 2y = 2
Now we have 6 + 2y = 2.
6 + 2y = 2
We want y by itself.
The 6 is in the way.
To remove 6, we take away 6.
We do it on both sides, so they stay equal.
6 + 2y โ 6 = 2 โ 6
6 and โ 6 make zero.
Cross them out.
2 minus 6 is โ4.
2 โ 6 = โ4
Now we have 2y = โ4.
2y = โ4
2y means 2 times y.
We want just y.
To remove times 2, we divide by 2.
We do it on both sides, so they stay equal.
2y2 = โ42
2 divided by 2 is 1.
So just y is left.
โ4 divided by 2 is โ2.
โ42 = โ2
So y = โ2.
y = โ2
6 Find z
We put x = 2 and y = โ2 into โก, the easiest one.
2 โ (โ2) โ z = 3
2 โ (โ2) is 4.
4 โ z = 3
We want z by itself.
The 4 is in the way.
To remove 4, we take away 4.
We do it on both sides, so they stay equal.
4 โ z โ 4 = 3 โ 4
4 and โ 4 make zero.
Cross them out.
3 minus 4 is โ1.
3 โ 4 = โ1
Now we have โz = โ1.
โz = โ1
โz means โ1 times z.
We want just z.
To remove times โ1, we divide by โ1.
We do it on both sides, so they stay equal.
โzโ1 = โ1โ1
โ1 divided by โ1 is 1.
So just z is left.
โ1 divided by โ1 is 1.
โ1โ1 = 1
So z = 1.
z = 1
So x = 2, y = โ2 and z = 1, all at the same time.
We write it as (2, โ2, 1).
(x, y, z) = (2, โ2, 1)
7 Check
Let's check in every equation.
We put x = 2, y = โ2, z = 1 into โ .
โ 2(2) + 3(โ2) + 1 = 4 โ 6 + 1 = โ1
We get โ1, the same as the right side.
Now โก.
โก 2 โ (โ2) โ 1 = 2 + 2 โ 1 = 3
We get 3, the same as the right side.
Now โข.
โข 2 โ (โ2) + 1 = 2 + 2 + 1 = 5
We get 5, the same as the right side.
All of them work.
So the answer is right!
Let's look back.
First: remove z from โ and โก.
Then: remove z from โก and โข.
Then: add the equations.
Then: find x.
Then: find y.
Then: find z.
Last: check.
Answer (x, y, z) = (2, โ2, 1)
โถ Watch it solved
The question
Question: solve x + y + z = 6, 2x + 3y โ z = 5 and 3x โ 2y + z = 19.
x + y + z = 6โ
2x + 3y โ z = 5โก
We call them โ , โก and โข.
We want the x, y and z that make all three true.
3x โ 2y + z = 19โข
The plan: remove one letter twice.
Then we have two equations with two letters, and we know how to solve those.
1 Remove z from โ and โก
Look at z in โ and โก: z and โz.
They are opposites, so adding removes z.
We write โ and โก under each other: x under x, y under y, z under z.
x + y + z = 6โ
2x + 3y โ z = 5โก
z and โz make zero.
Cross them out.
We add: the x parts, the y parts, and the numbers.
x + 2x = 3x.
y + 3y = 4y.
6 + 5 = 11.
x + 2x = 3x
y + 3y = 4y
6 + 5 = 11
Careful!
We add every part of both equations: each letter, and the numbers on the right too.
Careful: add every part, the numbers too
Now we have 3x + 4y = 11.
We call it โฃ.
It has no z.
3x + 4y = 11โฃ
2 Remove z from โก and โข
Look at z in โก and โข: โz and z.
They are opposites, so adding removes z.
We write โก and โข under each other: x under x, y under y, z under z.
2x + 3y โ z = 5โก
3x โ 2y + z = 19โข
โz and z make zero.
Cross them out.
We add: the x parts, the y parts, and the numbers.
2x + 3x = 5x.
3y โ 2y = y.
5 + 19 = 24.
2x + 3x = 5x
3y โ 2y = y
5 + 19 = 24
Now we have 5x + y = 24.
We call it โค.
It has no z.
5x + y = 24โค
Now โฃ and โค are two equations with two letters: x and y.
We solve them like before, by elimination.
We write โฃ and โค again, in columns.
3x + 4y = 11โฃ
5x + y = 24โค
3 Make the y numbers opposite
We want to remove y.
In โฃ it is 4y, in โค it is y.
We make them opposite: 4y and โ4y.
Then adding removes y.
We multiply every part of โค by โ4.
We do it on both sides, so they stay equal.
โ4 ร (5x + y) = โ4 ร 24โค ร โ4
โ4 times 5x is โ20x.
โ4 times y is โ4y.
โ4 times 24 is โ96.
โ4 ร 5x = โ20x, โ4 ร y = โ4y, โ4 ร 24 = โ96
We call it โฅ.
โ20x โ 4y = โ96โฅ
4 Add the equations
We write โฃ and โฅ under each other: x under x, y under y.
3x + 4y = 11โฃ
โ20x โ 4y = โ96โฅ
Look at y: 4y and โ4y.
They are opposites.
Added, they make zero.
4y and โ4y make zero.
Cross them out.
We add โฃ and โฅ: the x parts together, and the numbers together.
3x โ 20x = โ17x.
11 + (โ96) = โ85.
3x โ 20x = โ17x
11 + (โ96) = โ85
Now we have โ17x = โ85.
โ17x = โ85
5 Find x
โ17x means โ17 times x.
We want just x.
To remove times โ17, we divide by โ17.
We do it on both sides, so they stay equal.
โ17xโ17 = โ85โ17
โ17 divided by โ17 is 1.
So just x is left.
โ85 divided by โ17 is 5.
โ85โ17 = 5
So x = 5.
x = 5
6 Find y
We put x = 5 into โค.
5 times 5 is 25.
5(5) + y = 24
Now we have 25 + y = 24.
25 + y = 24
We want y by itself.
The 25 is in the way.
To remove 25, we take away 25.
We do it on both sides, so they stay equal.
25 + y โ 25 = 24 โ 25
25 and โ 25 make zero.
Cross them out.
24 minus 25 is โ1.
24 โ 25 = โ1
So y = โ1.
y = โ1
7 Find z
We put x = 5 and y = โ1 into โ , the easiest one.
5 + (โ1) + z = 6
5 + (โ1) is 4.
4 + z = 6
We want z by itself.
The 4 is in the way.
To remove 4, we take away 4.
We do it on both sides, so they stay equal.
4 + z โ 4 = 6 โ 4
4 and โ 4 make zero.
Cross them out.
6 minus 4 is 2.
6 โ 4 = 2
So z = 2.
z = 2
So x = 5, y = โ1 and z = 2, all at the same time.
We write it as (5, โ1, 2).
(x, y, z) = (5, โ1, 2)
8 Check
Let's check in every equation.
We put x = 5, y = โ1, z = 2 into โ .
โ 5 + (โ1) + 2 = 5 โ 1 + 2 = 6
We get 6, the same as the right side.
Now โก.
โก 2(5) + 3(โ1) โ 2 = 10 โ 3 โ 2 = 5
We get 5, the same as the right side.
Now โข.
โข 3(5) โ 2(โ1) + 2 = 15 + 2 + 2 = 19
We get 19, the same as the right side.
All of them work.
So the answer is right!
Let's look back.
First: remove z from โ and โก.
Then: remove z from โก and โข.
Then: make the y numbers opposite.
Then: add the equations.
Then: find x.
Then: find y.
Then: find z.
Last: check.
Answer (x, y, z) = (5, โ1, 2)
โถ Watch it solved