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Graphing inequalities

Algebra 1 ยท 22 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Draw the line
  2. Test a point
  3. Shade
  4. Check

The steps for Graph y > 2x - 1. Every solution names its steps, so you always know what comes next.

Worked examples

Graph y > 2x - 1 Easy

The question

Question: graph y > 2x โˆ’ 1.

y > 2x โˆ’ 1

The answer is not one point.

It is every point that makes this true.

That is a whole part of the grid.

answer = all the points that work

1 Draw the line

First we draw the line where both sides are equal: y = 2x โˆ’ 1.

y = 2x โˆ’ 1

The sign is more than, with no "or equal to".

So points on the line are not answers.

We draw it dashed, like the open circle on a number line.

> โ†’ dashed line

Draw the grid.

The x-axis goes across.

The y-axis goes up and down.

They meet at 0.

That point is called the origin.

b = โˆ’1.

Start on the y-axis at โˆ’1.

m = 2.

As a fraction: 2/1.

Go right 1,

then up 2.

Dot.

Join the dots: dashed.

2 Test a point

The line cuts the grid in two sides.

One side is the answer.

We test one point: (0, 0).

Zeros are easy to work with.

Put x = 0 and y = 0 in.

0 > 2(0) โˆ’ 1
0 > โˆ’1 true

Is 0 more than โˆ’1?

Yes, that is true.

So (0, 0) is an answer.

3 Shade

So we shade the side with (0, 0).

Every point there is an answer.

4 Check

Let's check with a point in the shaded part: (โˆ’2, โˆ’1).

Put x = โˆ’2 and y = โˆ’1 in.

โˆ’1 > 2(โˆ’2) โˆ’ 1
โˆ’1 > โˆ’5 true

True!

So the shading is right.

Let's look back.

First: draw the line.

Then: test a point.

Then: shade.

Last: check.

Answer
0 > โˆ’1 true

โ–ถ Watch it solved

Graph y <= -x + 3 Medium

The question

Question: graph y โ‰ค โˆ’x + 3.

y โ‰ค โˆ’x + 3

The answer is not one point.

It is every point that makes this true.

That is a whole part of the grid.

answer = all the points that work

1 Draw the line

First we draw the line where both sides are equal: y = โˆ’x + 3.

y = โˆ’x + 3

The sign has "or equal to".

So points on the line are answers too.

We draw it solid, like the filled circle on a number line.

โ‰ค โ†’ solid line

Draw the grid.

The x-axis goes across.

The y-axis goes up and down.

They meet at 0.

That point is called the origin.

b = 3.

Start on the y-axis at 3.

m = โˆ’1.

As a fraction: โˆ’1/1.

Go right 1,

then down 1.

Dot.

Join the dots: solid.

2 Test a point

The line cuts the grid in two sides.

One side is the answer.

We test one point: (0, 0).

Zeros are easy to work with.

Put x = 0 and y = 0 in.

0 โ‰ค โˆ’(0) + 3
0 โ‰ค 3 true

Is 0 less than or equal to 3?

Yes, that is true.

So (0, 0) is an answer.

3 Shade

So we shade the side with (0, 0).

Every point there is an answer.

4 Check

Let's check with a point in the shaded part: (โˆ’2, โˆ’1).

Put x = โˆ’2 and y = โˆ’1 in.

โˆ’1 โ‰ค โˆ’(โˆ’2) + 3
โˆ’1 โ‰ค 5 true

True!

So the shading is right.

Let's look back.

First: draw the line.

Then: test a point.

Then: shade.

Last: check.

Answer
0 โ‰ค 3 true

โ–ถ Watch it solved

Graph x + 2y < 4 Harder

The question

Question: graph x + 2y < 4.

x + 2y < 4

The answer is not one point.

It is every point that makes this true.

That is a whole part of the grid.

answer = all the points that work

1 Draw the line

First we draw the line where both sides are equal: x + 2y = 4.

x + 2y = 4

The sign is less than, with no "or equal to".

So points on the line are not answers.

We draw it dashed, like the open circle on a number line.

< โ†’ dashed line

On the x-axis, y = 0.

Put 0 in place of y.

x + 2 ร— 0 = 4

2 times 0 is 0.

Adding 0 changes nothing.

So x = 4.

x = 4

On the y-axis, x = 0.

Put 0 in place of x.

0 + 2y = 4

0 plus 2y is just 2y.

2y = 4

2y means 2 times y.

We want just y.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2y2 = 42

2 divided by 2 is 1.

So just y is left.

4 divided by 2 is 2.

42 = 2

So y = 2.

So the line crosses the axes at (4, 0) and (0, 2).

y = 2

Draw the grid.

The x-axis goes across.

The y-axis goes up and down.

They meet at 0.

That point is called the origin.

Put the two crossing points on the grid,

and join them: dashed.

2 Test a point

The line cuts the grid in two sides.

One side is the answer.

We test one point: (0, 0).

Zeros are easy to work with.

Put x = 0 and y = 0 in.

0 + 2(0) < 4
0 < 4 true

Is 0 less than 4?

Yes, that is true.

So (0, 0) is an answer.

3 Shade

So we shade the side with (0, 0).

Every point there is an answer.

4 Check

Let's check with a point in the shaded part: (โˆ’2, โˆ’1).

Put x = โˆ’2 and y = โˆ’1 in.

(โˆ’2) + 2(โˆ’1) < 4
โˆ’4 < 4 true

True!

So the shading is right.

Let's look back.

First: draw the line.

Then: test a point.

Then: shade.

Last: check.

Answer
0 < 4 true

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. graph y > 2x - 1
    Answer
    0 > โˆ’1 true
  2. graph y < x + 2
    Answer
    0 < 2 true
  3. graph y > -x + 3
    Answer
    0 > 3 false
  4. graph y < 3x - 2
    Answer
    0 < โˆ’2 false
  5. graph y < -2x + 4
    Answer
    0 < 4 true
  6. graph y > x - 3
    Answer
    0 > โˆ’3 true
  7. graph y < 2x + 1
    Answer
    0 < 1 true
  8. graph y > -x - 2
    Answer
    0 > โˆ’2 true

Medium

  1. graph y <= -x + 3
    Answer
    0 โ‰ค 3 true
  2. graph y >= 2x - 4
    Answer
    0 โ‰ฅ โˆ’4 true
  3. graph y <= 1/2x + 1
    Answer
    0 โ‰ค 1 true
  4. graph y >= -1/2x - 2
    Answer
    0 โ‰ฅ โˆ’2 true
  5. graph y >= x + 2
    Answer
    0 โ‰ฅ 2 false
  6. graph y <= -2x - 3
    Answer
    0 โ‰ค โˆ’3 false
  7. graph y < 3
    Answer
    0 < 3 true
  8. graph x > 2
    Answer
    0 > 2 false
  9. graph x <= -1
    Answer
    0 โ‰ค โˆ’1 false

Harder

  1. graph x + 2y < 4
    Answer
    0 < 4 true
  2. graph 3x - 2y >= 6
    Answer
    0 โ‰ฅ 6 false
  3. graph 2x + y > -4
    Answer
    0 > โˆ’4 true
  4. graph y >= 2x
    Answer
    0 โ‰ฅ 2 false
  5. graph -x + 3y <= 6
    Answer
    0 โ‰ค 6 true