Steply

Parallel and perpendicular lines

Algebra 1 ยท 26 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Slope of โ‘ 
  2. Slope of โ‘ก
  3. Compare the slopes
  4. Check

The steps for Are y = 2x + 1 and y = 2x - 3 parallel, perpendicular or neither. Every solution names its steps, so you always know what comes next.

Worked examples

Are y = 2x + 1 and y = 2x - 3 parallel, perpendicular or neither Easy

The question

Question: are y = 2x + 1 and y = 2x โˆ’ 3 parallel, perpendicular or neither.

โ‘  y = 2x + 1 and โ‘ก y = 2x โˆ’ 3

The slopes tell us which.

Same slope: parallel.

Flip the slope and change its sign: perpendicular.

parallel: same slope
perpendicular: flip and change the sign

1 Slope of โ‘ 

m is the number in front of x: 2.

It is the slope.

b is 1.

m1 = 2
b = 1

2 Slope of โ‘ก

m is the number in front of x: 2.

It is the slope.

b is โˆ’3.

m2 = 2
b = โˆ’3

3 Compare the slopes

Both slopes are 2.

The same steepness.

2 = 2

But they start at different places: 1 and โˆ’3.

b = 1 and b = โˆ’3

So the lines are parallel: they never meet.

โ‘  and โ‘ก are parallel

4 Check

Let's see it on the grid.

Draw both lines.

They never meet.

Let's look back.

First: slope of โ‘ .

Then: slope of โ‘ก.

Then: compare the slopes.

Last: check.

Answer
โ‘  and โ‘ก are parallel

โ–ถ Watch it solved

Are y = 2/3x + 1 and y = -3/2x - 2 parallel, perpendicular or neither Medium

The question

Question: are y = (2/3)x + 1 and y = โˆ’(3/2)x โˆ’ 2 parallel, perpendicular or neither.

โ‘  y = 23x + 1 and โ‘ก y = โˆ’32x โˆ’ 2

The slopes tell us which.

Same slope: parallel.

Flip the slope and change its sign: perpendicular.

parallel: same slope
perpendicular: flip and change the sign

1 Slope of โ‘ 

m is the number in front of x: 2/3.

It is the slope.

b is 1.

m1 = 23
b = 1

2 Slope of โ‘ก

m is the number in front of x: โˆ’3/2.

It is the slope.

b is โˆ’2.

m2 = โˆ’32
b = โˆ’2

3 Compare the slopes

2/3 and โˆ’3/2 are not the same.

So the lines are not parallel.

23 โ‰  โˆ’32

Flip it: 3/2.

Then change the sign: โˆ’3/2.

23 โ†’ flip: 32
โ†’ change the sign: โˆ’32

That is the second slope, โˆ’3/2!

โˆ’32 = โˆ’32

Another way to check: multiply them.

2/3 times โˆ’3/2 is โˆ’1.

Perpendicular slopes always multiply to โˆ’1.

23 ร— (โˆ’32) = โˆ’1
perpendicular slopes multiply to โˆ’1

So the lines are perpendicular: they meet at a square corner.

โ‘  and โ‘ก are perpendicular

4 Check

Let's see it on the grid.

Draw both lines.

They meet at a square corner.

Let's look back.

First: slope of โ‘ .

Then: slope of โ‘ก.

Then: compare the slopes.

Last: check.

Answer
โ‘  and โ‘ก are perpendicular

โ–ถ Watch it solved

Are 2x + 3y = 6 and 3x - 2y = 4 parallel, perpendicular or neither Harder

The question

Question: are 2x + 3y = 6 and 3x โˆ’ 2y = 4 parallel, perpendicular or neither.

โ‘  2x + 3y = 6 and โ‘ก 3x โˆ’ 2y = 4

The slopes tell us which.

Same slope: parallel.

Flip the slope and change its sign: perpendicular.

parallel: same slope
perpendicular: flip and change the sign

1 Slope of โ‘ 

โ‘  is not y = mx + b yet.

So we write it as y = mx + b first.

We want y by itself.

The 2x is in the way.

To remove 2x, we take away 2x.

We do it on both sides, so they stay equal.

2x + 3y โˆ’ 2x = 6 โˆ’ 2x

2x and โˆ’ 2x make zero.

Cross them out.

Write what is left.

3y = 6 โˆ’ 2x

We write the x part first, like in y = mx + b.

Each part keeps its sign.

3y = โˆ’2x + 6

3y means 3 times y.

We want just y.

To remove times 3, we divide by 3.

We do it on both sides, so they stay equal.

3y3 = โˆ’2x + 63

3 divided by 3 is 1.

So just y is left.

The 3 divides the whole right side.

So it divides every part: โˆ’2x and 6.

Each part keeps its sign on top.

y = โˆ’2x3 + 63

Minus over plus is minus.

โˆ’2x/3 is the same as โˆ’2/3 times x.

โˆ’2x3 = โˆ’23x

6 divided by 3 is 2.

63 = 2

So y = โˆ’(2/3)x + 2.

y = โˆ’23x + 2

m is the number in front of x: โˆ’2/3.

It is the slope.

m1 = โˆ’23
b = 2

2 Slope of โ‘ก

โ‘ก is not y = mx + b yet.

So we write it as y = mx + b first.

We want y by itself.

The 3x is in the way.

To remove 3x, we take away 3x.

We do it on both sides, so they stay equal.

3x โˆ’ 2y โˆ’ 3x = 4 โˆ’ 3x

3x and โˆ’ 3x make zero.

Cross them out.

Write what is left.

โˆ’2y = 4 โˆ’ 3x

We write the x part first, like in y = mx + b.

Each part keeps its sign.

โˆ’2y = โˆ’3x + 4

โˆ’2y means โˆ’2 times y.

We want just y.

To remove times โˆ’2, we divide by โˆ’2.

We do it on both sides, so they stay equal.

โˆ’2yโˆ’2 = โˆ’3x + 4โˆ’2

โˆ’2 divided by โˆ’2 is 1.

So just y is left.

The โˆ’2 divides the whole right side.

So it divides every part: โˆ’3x and 4.

Each part keeps its sign on top.

y = โˆ’3xโˆ’2 + 4โˆ’2

Minus over minus is plus.

โˆ’3x over โˆ’2 is the same as 3/2 times x.

โˆ’3xโˆ’2 = 32x

Plus over minus is minus.

4 divided by โˆ’2 is โˆ’2.

4โˆ’2 = โˆ’2

So y = (3/2)x โˆ’ 2.

y = 32x โˆ’ 2

m is the number in front of x: 3/2.

It is the slope.

m2 = 32
b = โˆ’2

3 Compare the slopes

โˆ’2/3 and 3/2 are not the same.

So the lines are not parallel.

โˆ’23 โ‰  32

Flip it: โˆ’3/2.

Then change the sign: 3/2.

โˆ’23 โ†’ flip: โˆ’32
โ†’ change the sign: 32

That is the second slope, 3/2!

32 = 32

Another way to check: multiply them.

โˆ’2/3 times 3/2 is โˆ’1.

Perpendicular slopes always multiply to โˆ’1.

โˆ’23 ร— 32 = โˆ’1
perpendicular slopes multiply to โˆ’1

So the lines are perpendicular: they meet at a square corner.

โ‘  and โ‘ก are perpendicular

4 Check

Let's see it on the grid.

Draw both lines.

They meet at a square corner.

Let's look back.

First: slope of โ‘ .

Then: slope of โ‘ก.

Then: compare the slopes.

Last: check.

Answer
โ‘  and โ‘ก are perpendicular

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. are y = 2x + 1 and y = 2x - 3 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are parallel
  2. are y = 3x - 2 and y = -1/3x + 4 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are perpendicular
  3. are y = -x + 5 and y = x - 2 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are perpendicular
  4. are y = 4x + 1 and y = 2x + 1 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก : neither
  5. line through (2, 5) parallel to y = 2x - 1
    Answer
    y = 2x + 1
  6. line through (1, 5) parallel to y = 3x + 1
    Answer
    y = 3x + 2
  7. line through (2, 3) perpendicular to y = 2x - 1
    Answer
    y = โˆ’12x + 4
  8. line through (3, 1) perpendicular to y = x + 4
    Answer
    y = โˆ’x + 4
  9. line through (3, 2) perpendicular to y = 3x - 1
    Answer
    y = โˆ’13x + 3
  10. line through (1, 4) parallel to y = -2x + 3
    Answer
    y = โˆ’2x + 6

Medium

  1. are y = 2/3x + 1 and y = -3/2x - 2 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are perpendicular
  2. are 2x + y = 4 and y = -2x + 1 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are parallel
  3. are y = 1/2x + 3 and x - 2y = 4 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are parallel
  4. are y = 2x + 3 and y = 1/2x - 1 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก : neither
  5. are y = -4x + 2 and y = 1/4x - 3 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are perpendicular
  6. line through (4, 1) perpendicular to y = 2x + 5
    Answer
    y = โˆ’12x + 3
  7. line through (-2, 1) parallel to y = 2x - 3
    Answer
    y = 2x + 5
  8. line through (2, -1) parallel to 2x + y = 4
    Answer
    y = โˆ’2x + 3
  9. line through (3, 2) perpendicular to y = -3x + 1
    Answer
    y = 13x + 1
  10. line through (-1, 4) perpendicular to y = -x + 2
    Answer
    y = x + 5

Harder

  1. are 2x + 3y = 6 and 3x - 2y = 4 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are perpendicular
  2. are y = 3x + 2 and 6x - 2y = -4 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are the same line
  3. are x = 3 and y = -2 parallel, perpendicular or neither
    Answer
    โ‘  and โ‘ก are perpendicular
  4. line through (2, 3) perpendicular to y = 4
    Answer
    x = 2
  5. line through (1, -2) parallel to x = 3
    Answer
    x = 1
  6. line through (2, 3) perpendicular to x - 2y = 2
    Answer
    y = โˆ’2x + 7