The question
Question: work out ln(eโด).
ln(e4)
e is a special number, like ฯ.
It is about 2.718.
A log with base e is written ln.
We say "natural log".
e โ 2.718
ln = loge
1 What the log asks
A log is a power.
ln(eโด) asks: e to what power is eโด?
a log is a power
e to the power what is eโด?
e? = e4
2 Find the power
It is already e to a power: the power is 4.
ln and e undo each other.
ln and e undo each other
So the power is 4.
e4 = e4
So ln(eโด) = 4.
ln(e4) = 4
Let's look back.
First: what the log asks.
Last: find the power.
โถ Watch it solved
The question
Question: solve e to the power (2x) = 9.
x is up in the power.
e2x = 9
e is a special number, like ฯ.
It is about 2.718.
A log with base e is written ln.
We say "natural log".
e โ 2.718
ln = loge
1 Take ln of both sides
To bring the power down, we use a log.
With e, we use ln.
We do it on both sides, so they stay equal.
ln(e2x) = ln 9
Careful!
x is up in the power.
Dividing by e does not bring it down.
Only a log does.
Careful: not x = 9 รท e โ
2 ln and e undo each other
ln asks: e to what power?
For e to the power k, the answer is k.
So ln and e undo each other.
ln(ek) = k
So the left side is just 2x.
2x = ln 9
3 Remove the 2
2x means 2 times x.
We want just x.
To remove times 2, we divide by 2.
We do it on both sides, so they stay equal.
2x2 = ln 92
2 divided by 2 is 1.
So just x is left.
So x = ln 9/2.
This is the exact answer.
x = ln 92
4 Use a calculator
With a calculator, ln 9 is about 2.1972.
Then 2.1972 รท 2 is about 1.099.
ln 9 โ 2.1972
2.1972 รท 2 โ 1.099
So x is about 1.099.
x โ 1.099
So x = ln 9/2, about 1.099 to three decimal places.
5 Check
Let's check with a calculator.
The power gives about 9.0.
That is 9.
It works!
Check: e2(1.099) โ 9.0
Let's look back.
First: take ln of both sides.
Then: ln and e undo each other.
Then: remove the 2.
Then: use a calculator.
Last: check.
โถ Watch it solved
The question
Question: solve e to the power (2x + 1) = 9.
x is up in the power.
e2x + 1 = 9
e is a special number, like ฯ.
It is about 2.718.
A log with base e is written ln.
We say "natural log".
e โ 2.718
ln = loge
1 Take ln of both sides
To bring the power down, we use a log.
With e, we use ln.
We do it on both sides, so they stay equal.
ln(e2x + 1) = ln 9
Careful!
x is up in the power.
Dividing by e does not bring it down.
Only a log does.
Careful: not x = 9 รท e โ
2 ln and e undo each other
ln asks: e to what power?
For e to the power k, the answer is k.
So ln and e undo each other.
ln(ek) = k
So the left side is just 2x + 1.
2x + 1 = ln 9
3 Remove the + 1
We want 2x by itself.
The + 1 is in the way.
To remove + 1, we take away 1.
We do it on both sides, so they stay equal.
2x + 1 โ 1 = ln 9 โ 1
+ 1 and โ 1 make zero.
Cross them out.
We keep it exact: 2x = ln 9 โ 1.
2x = ln 9 โ 1
4 Remove the 2
2x means 2 times x.
We want just x.
To remove times 2, we divide by 2.
We do it on both sides, so they stay equal.
2x2 = ln 9 โ 12
2 divided by 2 is 1.
So just x is left.
So x = (ln 9 โ 1)/2.
This is the exact answer.
x = ln 9 โ 12
5 Use a calculator
With a calculator, ln 9 is about 2.1972.
Then (2.1972 โ 1) รท 2 is about 0.599.
ln 9 โ 2.1972
(2.1972 โ 1) รท 2 โ 0.599
So x is about 0.599.
x โ 0.599
So x = (ln 9 โ 1)/2, about 0.599 to three decimal places.
6 Check
Let's check with a calculator.
The power gives about 9.0.
That is 9.
It works!
Check: e2(0.599) + 1 โ 9.0
Let's look back.
First: take ln of both sides.
Then: ln and e undo each other.
Then: remove the + 1.
Then: remove the 2.
Then: use a calculator.
Last: check.
โถ Watch it solved