Steply

Solve e^(3x) = 20

Step by step, with the reason for every step · Natural logarithms · Algebra 2

Step by step

The question

Question: solve e to the power (3x) = 20.

x is up in the power.

e3x = 20

e is a special number, like π.

It is about 2.718.

A log with base e is written ln.

We say "natural log".

e ≈ 2.718
ln = loge

1 Take ln of both sides

To bring the power down, we use a log.

With e, we use ln.

We do it on both sides, so they stay equal.

ln(e3x) = ln 20

Careful!

x is up in the power.

Dividing by e does not bring it down.

Only a log does.

Careful: not x = 20 ÷ e ✗

2 ln and e undo each other

ln asks: e to what power?

For e to the power k, the answer is k.

So ln and e undo each other.

ln(ek) = k

So the left side is just 3x.

3x = ln 20

3 Remove the 3

3x means 3 times x.

We want just x.

To remove times 3, we divide by 3.

We do it on both sides, so they stay equal.

3x3 = ln 203

3 divided by 3 is 1.

So just x is left.

So x = ln 20/3.

This is the exact answer.

x = ln 203

4 Use a calculator

With a calculator, ln 20 is about 2.9957.

Then 2.9957 ÷ 3 is about 0.999.

ln 20 ≈ 2.9957
2.9957 ÷ 3 ≈ 0.999

So x is about 0.999.

x ≈ 0.999

So x = ln 20/3, about 0.999 to three decimal places.

5 Check

Let's check with a calculator.

The power gives about 20.0.

That is 20.

It works!

Check: e3(0.999) ≈ 20.0

Let's look back.

First: take ln of both sides.

Then: ln and e undo each other.

Then: remove the 3.

Then: use a calculator.

Last: check.

Answer
x ≈ 0.999

Your turn

Try this one yourself, then check:

Solve e3x = 9
Show the answer
x ≈ 0.732

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