Worked examples
The question
Question: find the slant asymptote of f(x) = (xยฒ + 1)/(x โ 1).
f(x) = x2 + 1x โ 1
An asymptote is a line the graph gets closer and closer to.
We draw it dashed.
asymptote: a line the graph gets close to
1 Compare the powers
The top has xยฒ: power 2.
The bottom has x: power 1.
top : power 2, bottom: power 1
The top power is one bigger.
Then there is no flat asymptote.
Instead, the graph gets close to a slanted line: a slant asymptote.
Dividing finds it.
top power one bigger โ a slanted line
2 Set it up
We write it like long division with numbers.
x โ 1 goes outside, xยฒ + 1 inside.
There is no x part.
We write 0x, so the columns line up.
3 First part of the answer
Divide the first parts: xยฒ divided by x is x.
We write it on top.
Multiply: x times (x โ 1) is xยฒ โ x.
We write it under, with a minus: we take it away.
xยฒ take away xยฒ is 0.
That is why we chose x.
0x take away โx is x.
Bring down the next part: 1.
4 Second part of the answer
Divide the first parts: x divided by x is 1.
We write it on top.
Multiply: 1 times (x โ 1) is x โ 1.
We write it under, with a minus: we take it away.
x take away x is 0.
That is why we chose 1.
1 take away โ1 is 2.
2 has no x.
We can't divide it by x.
So 2 is the remainder: what is left over.
So f(x) is x + 1, plus 2/(x โ 1).
f(x) = x + 1 + 2x โ 1
5 Read the slant asymptote
When x is big, 2/(x โ 1) is tiny.
At x = 100 it is 2/99: about 0.02.
Almost 0.
x = 100: 299 โ 0.02
So for a big x, f(x) is close to x + 1.
The slant asymptote is y = x + 1.
slant asymptote : y = x + 1
Careful!
The remainder part is not in the line.
It gets smaller and smaller, so we leave it out.
Careful: not y = x + 1 + 2x โ 1 โ
6 Vertical asymptote
The bottom: x โ 1 = 0 when x = 1.
x โ 1 = 0 โ x = 1
We can never divide by 0.
The top is not 0 there, so near it the graph shoots up or down: a vertical asymptote.
รท 0: not allowed
So the asymptotes are y = x + 1 and x = 1.
= y = x + 1, x = 1
7 Check
Let's check with a picture.
The vertical asymptote x = 1, dashed.
The slant asymptote y = x + 1, dashed.
The graph of f: on each side it gets close to both dashed lines.
And with numbers: at x = 100, f is about 101.02, and the line gives 101.
Very close.
It works!
x = 100: f(100) โ 101.02, line: 101
Let's look back.
First: compare the powers.
Then: set it up.
Then: first part of the answer.
Then: second part of the answer.
Then: read the slant asymptote.
Then: vertical asymptote.
Last: check.
Answer = y = x + 1, x = 1
โถ Watch it solved
The question
Question: find the asymptotes of f(x) = (xยฒ โ x โ 6)/(x โ 1).
f(x) = x2 โ x โ 6x โ 1
An asymptote is a line the graph gets closer and closer to.
We draw it dashed.
asymptote: a line the graph gets close to
1 Compare the powers
The top has xยฒ: power 2.
The bottom has x: power 1.
top : power 2, bottom: power 1
The top power is one bigger.
Then there is no flat asymptote.
Instead, the graph gets close to a slanted line: a slant asymptote.
Dividing finds it.
top power one bigger โ a slanted line
2 Set it up
We write it like long division with numbers.
x โ 1 goes outside, xยฒ โ x โ 6 inside.
3 First part of the answer
Divide the first parts: xยฒ divided by x is x.
We write it on top.
Multiply: x times (x โ 1) is xยฒ โ x.
We write it under, with a minus: we take it away.
xยฒ take away xยฒ is 0.
That is why we chose x.
โx take away โx is 0x.
Bring down the next part: โ6.
4 Second part of the answer
Divide the first parts: 0x divided by x is 0.
We write it on top.
Multiply: 0 times (x โ 1) is 0.
We write it under, with a minus: we take it away.
0x take away 0x is 0.
That is why we chose 0.
โ6 take away 0 is โ6.
โ6 has no x.
We can't divide it by x.
So โ6 is the remainder: what is left over.
So f(x) is x, minus 6/(x โ 1).
f(x) = x โ 6x โ 1
5 Read the slant asymptote
When x is big, 6/(x โ 1) is tiny.
At x = 100 it is 6/99: about 0.06.
Almost 0.
x = 100: 699 โ 0.06
So for a big x, f(x) is close to x.
The slant asymptote is y = x.
slant asymptote : y = x
Careful!
The remainder part is not in the line.
It gets smaller and smaller, so we leave it out.
Careful: not y = x โ 6x โ 1 โ
6 Vertical asymptote
The bottom: x โ 1 = 0 when x = 1.
x โ 1 = 0 โ x = 1
We can never divide by 0.
The top is not 0 there, so near it the graph shoots up or down: a vertical asymptote.
รท 0: not allowed
So the asymptotes are y = x and x = 1.
= y = x, x = 1
7 Check
Let's check with a picture.
The vertical asymptote x = 1, dashed.
The slant asymptote y = x, dashed.
The graph of f: on each side it gets close to both dashed lines.
And with numbers: at x = 100, f is about 99.94, and the line gives 100.
Very close.
It works!
x = 100: f(100) โ 99.94, line: 100
Let's look back.
First: compare the powers.
Then: set it up.
Then: first part of the answer.
Then: second part of the answer.
Then: read the slant asymptote.
Then: vertical asymptote.
Last: check.
โถ Watch it solved
The question
Question: find the asymptotes of f(x) = (3xยฒ + 2x โ 1)/(x + 2).
f(x) = 3x2 + 2x โ 1x + 2
An asymptote is a line the graph gets closer and closer to.
We draw it dashed.
asymptote: a line the graph gets close to
1 Compare the powers
The top has xยฒ: power 2.
The bottom has x: power 1.
top : power 2, bottom: power 1
The top power is one bigger.
Then there is no flat asymptote.
Instead, the graph gets close to a slanted line: a slant asymptote.
Dividing finds it.
top power one bigger โ a slanted line
2 Set it up
We write it like long division with numbers.
x + 2 goes outside, 3xยฒ + 2x โ 1 inside.
3 First part of the answer
Divide the first parts: 3xยฒ divided by x is 3x.
We write it on top.
Multiply: 3x times (x + 2) is 3xยฒ + 6x.
We write it under, with a minus: we take it away.
3xยฒ take away 3xยฒ is 0.
That is why we chose 3x.
2x take away 6x is โ4x.
Bring down the next part: โ1.
4 Second part of the answer
Divide the first parts: โ4x divided by x is โ4.
We write it on top.
Multiply: โ4 times (x + 2) is โ4x โ 8.
We write it under, with a minus: we take it away.
โ4x take away โ4x is 0.
That is why we chose โ4.
โ1 take away โ8 is 7.
7 has no x.
We can't divide it by x.
So 7 is the remainder: what is left over.
So f(x) is 3x โ 4, plus 7/(x + 2).
f(x) = 3x โ 4 + 7x + 2
5 Read the slant asymptote
When x is big, 7/(x + 2) is tiny.
At x = 100 it is 7/102: about 0.07.
Almost 0.
x = 100: 7102 โ 0.07
So for a big x, f(x) is close to 3x โ 4.
The slant asymptote is y = 3x โ 4.
slant asymptote : y = 3x โ 4
Careful!
The remainder part is not in the line.
It gets smaller and smaller, so we leave it out.
Careful: not y = 3x โ 4 + 7x + 2 โ
6 Vertical asymptote
The bottom: x + 2 = 0 when x = โ2.
x + 2 = 0 โ x = โ2
We can never divide by 0.
The top is not 0 there, so near it the graph shoots up or down: a vertical asymptote.
รท 0: not allowed
So the asymptotes are y = 3x โ 4 and x = โ2.
= y = 3x โ 4, x = โ2
7 Check
Let's check with a picture.
The vertical asymptote x = โ2, dashed.
The slant asymptote y = 3x โ 4, dashed.
The graph of f: on each side it gets close to both dashed lines.
And with numbers: at x = 100, f is about 296.07, and the line gives 296.
Very close.
It works!
x = 100: f(100) โ 296.07, line: 296
Let's look back.
First: compare the powers.
Then: set it up.
Then: first part of the answer.
Then: second part of the answer.
Then: read the slant asymptote.
Then: vertical asymptote.
Last: check.
Answer = y = 3x โ 4, x = โ2
โถ Watch it solved