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Asymptotes of f(x) = (2x^2 + 5x - 4)/(x + 3)

Step by step, with the reason for every step · Slant asymptotes of rational functions · Algebra 2

Step by step

The question

Question: find the asymptotes of f(x) = (2x² + 5x − 4)/(x + 3).

f(x) = 2x2 + 5x − 4x + 3

An asymptote is a line the graph gets closer and closer to.

We draw it dashed.

asymptote: a line the graph gets close to

1 Compare the powers

The top has x²: power 2.

The bottom has x: power 1.

top : power 2, bottom: power 1

The top power is one bigger.

Then there is no flat asymptote.

Instead, the graph gets close to a slanted line: a slant asymptote.

Dividing finds it.

top power one bigger → a slanted line

2 Set it up

We write it like long division with numbers.

x + 3 goes outside, 2x² + 5x − 4 inside.

3 First part of the answer

Divide the first parts: 2x² divided by x is 2x.

We write it on top.

Multiply: 2x times (x + 3) is 2x² + 6x.

We write it under, with a minus: we take it away.

2x² take away 2x² is 0.

That is why we chose 2x.

5x take away 6x is −x.

Bring down the next part: −4.

4 Second part of the answer

Divide the first parts: −x divided by x is −1.

We write it on top.

Multiply: −1 times (x + 3) is −x − 3.

We write it under, with a minus: we take it away.

−x take away −x is 0.

That is why we chose −1.

−4 take away −3 is −1.

−1 has no x.

We can't divide it by x.

So −1 is the remainder: what is left over.

So f(x) is 2x − 1, minus 1/(x + 3).

f(x) = 2x − 1 − 1x + 3

5 Read the slant asymptote

When x is big, 1/(x + 3) is tiny.

At x = 100 it is 1/103: about 0.01.

Almost 0.

x = 100: 1103 ≈ 0.01

So for a big x, f(x) is close to 2x − 1.

The slant asymptote is y = 2x − 1.

slant asymptote : y = 2x − 1

Careful!

The remainder part is not in the line.

It gets smaller and smaller, so we leave it out.

Careful: not y = 2x − 1 − 1x + 3 ✗

6 Vertical asymptote

The bottom: x + 3 = 0 when x = −3.

x + 3 = 0 → x = −3

We can never divide by 0.

The top is not 0 there, so near it the graph shoots up or down: a vertical asymptote.

÷ 0: not allowed

So the asymptotes are y = 2x − 1 and x = −3.

= y = 2x − 1, x = −3

7 Check

Let's check with a picture.

The vertical asymptote x = −3, dashed.

The slant asymptote y = 2x − 1, dashed.

The graph of f: on each side it gets close to both dashed lines.

And with numbers: at x = 100, f is about 198.99, and the line gives 199.

Very close.

It works!

x = 100: f(100) ≈ 198.99, line: 199

Let's look back.

First: compare the powers.

Then: set it up.

Then: first part of the answer.

Then: second part of the answer.

Then: read the slant asymptote.

Then: vertical asymptote.

Last: check.

Answer
= y = 2x − 1, x = −3

Your turn

Try this one yourself, then check:

asymptotes of f(x) = 2x2 + 2x − 1x + 4
Show the answer
y = 2x − 6, x = −4

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