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Perpendicular bisector of a segment

Geometry ยท 20 problems, easy to harder

โ–ถ Watch the first one solved

How we do it

  1. Find the midpoint
  2. Slope of AB
  3. Perpendicular slope
  4. Write the equation
  5. Draw it
  6. Check

The steps for Perpendicular bisector of (1, 2) and (5, 6). Every solution names its steps, so you always know what comes next.

Worked examples

Perpendicular bisector of (1, 2) and (5, 6) Easy

The question

Question: find the perpendicular bisector of A(1, 2) and B(5, 6).

perpendicular bisector of A(1, 2) and B(5, 6)

The perpendicular bisector cuts A B in half, at a right angle.

So it goes through the middle of A B.

bisector = cuts AB in half
perpendicular = at 90ยฐ to AB

1 Find the midpoint

The midpoint is the average of the x's and the average of the y's: (3, 4).

M = (1 + 52, 2 + 62) = (3, 4)

2 Slope of AB

The top is the change in y: second y minus first y.

The bottom is the change in x: second x minus first x.

That is 4/4, so 1.

slope of AB = 6 โˆ’ 25 โˆ’ 1 = 44 = 1

3 Perpendicular slope

Perpendicular slopes: flip the fraction and change the sign.

1 becomes โˆ’1.

perpendicular slope = โˆ’1

Check: 1 times โˆ’1 is negative 1, as for every perpendicular pair.

1 โ†’ flip, change sign โ†’ โˆ’1

Careful!

The slope of A B itself would give a line along A B, not across it.

We need the perpendicular slope.

Careful: not slope 1 โœ—

4 Write the equation

The line is y = m x + b with m = โˆ’1.

It goes through M: put x = 3 and y = 4 in.

4 = โˆ’1 ร— 3 + b

โˆ’1 times 3 is โˆ’3.

4 = โˆ’3 + b

To get b alone, add 3 on both sides: b = 7.

b = 7

So the perpendicular bisector is y = โˆ’x + 7.

= y = โˆ’x + 7

5 Draw it

Let's draw it on the grid.

A and B, and the segment between them.

M in the middle.

The bisector goes through M, across A B.

It meets A B at a right angle.

6 Check

Let's check with another point on the line, (4, 3).

Its distance squared to A and to B is the same: 10.

Every point on the bisector is as far from A as from B.

So it is right!

point (4, 3) on the line: to Aยฒ = 10, to Bยฒ = 10

Let's look back.

First: find the midpoint.

Then: slope of AB.

Then: perpendicular slope.

Then: write the equation.

Then: draw it.

Last: check.

Answer
= y = โˆ’x + 7

โ–ถ Watch it solved

Perpendicular bisector of (2, 3) and (6, 1) Medium

The question

Question: find the perpendicular bisector of A(2, 3) and B(6, 1).

perpendicular bisector of A(2, 3) and B(6, 1)

The perpendicular bisector cuts A B in half, at a right angle.

So it goes through the middle of A B.

bisector = cuts AB in half
perpendicular = at 90ยฐ to AB

1 Find the midpoint

The midpoint is the average of the x's and the average of the y's: (4, 2).

M = (2 + 62, 3 + 12) = (4, 2)

2 Slope of AB

The top is the change in y: second y minus first y.

The bottom is the change in x: second x minus first x.

That is โˆ’2/4, so โˆ’1/2.

slope of AB = 1 โˆ’ 36 โˆ’ 2 = โˆ’24 = โˆ’12

3 Perpendicular slope

Perpendicular slopes: flip the fraction and change the sign.

โˆ’1/2 becomes 2.

perpendicular slope = 2

Check: โˆ’1/2 times 2 is negative 1, as for every perpendicular pair.

โˆ’12 โ†’ flip, change sign โ†’ 2

Careful!

The slope of A B itself would give a line along A B, not across it.

We need the perpendicular slope.

Careful: not slope โˆ’12 โœ—

4 Write the equation

The line is y = m x + b with m = 2.

It goes through M: put x = 4 and y = 2 in.

2 = 2 ร— 4 + b

2 times 4 is 8.

2 = 8 + b

To get b alone, take away 8 on both sides: b = โˆ’6.

b = โˆ’6

So the perpendicular bisector is y = 2x โˆ’ 6.

= y = 2x โˆ’ 6

5 Draw it

Let's draw it on the grid.

A and B, and the segment between them.

M in the middle.

The bisector goes through M, across A B.

It meets A B at a right angle.

6 Check

Let's check with another point on the line, (5, 4).

Its distance squared to A and to B is the same: 10.

Every point on the bisector is as far from A as from B.

So it is right!

point (5, 4) on the line: to Aยฒ = 10, to Bยฒ = 10

Let's look back.

First: find the midpoint.

Then: slope of AB.

Then: perpendicular slope.

Then: write the equation.

Then: draw it.

Last: check.

Answer
= y = 2x โˆ’ 6

โ–ถ Watch it solved

Perpendicular bisector of (-3, 8) and (9, -2) Harder

The question

Question: find the perpendicular bisector of A(โˆ’3, 8) and B(9, โˆ’2).

perpendicular bisector of A(โˆ’3, 8) and B(9, โˆ’2)

The perpendicular bisector cuts A B in half, at a right angle.

So it goes through the middle of A B.

bisector = cuts AB in half
perpendicular = at 90ยฐ to AB

1 Find the midpoint

The midpoint is the average of the x's and the average of the y's: (3, 3).

M = (โˆ’3 + 92, 8 + (โˆ’2)2) = (3, 3)

2 Slope of AB

The top is the change in y: second y minus first y.

The bottom is the change in x: second x minus first x.

That is โˆ’10/12, so โˆ’5/6.

slope of AB = โˆ’2 โˆ’ 89 โˆ’ (โˆ’3) = โˆ’1012 = โˆ’56

3 Perpendicular slope

Perpendicular slopes: flip the fraction and change the sign.

โˆ’5/6 becomes 6/5.

perpendicular slope = 65

Check: โˆ’5/6 times 6/5 is negative 1, as for every perpendicular pair.

โˆ’56 โ†’ flip, change sign โ†’ 65

Careful!

The slope of A B itself would give a line along A B, not across it.

We need the perpendicular slope.

Careful: not slope โˆ’56 โœ—

4 Write the equation

The line is y = m x + b with m = 6/5.

It goes through M: put x = 3 and y = 3 in.

3 = 65 ร— 3 + b

6/5 times 3 is 18/5.

3 = 185 + b

To get b alone, take away 18/5 on both sides: b = โˆ’3/5.

b = โˆ’35

So the perpendicular bisector is y = 6/5, times x, minus 3/5.

= y = 65x โˆ’ 35

5 Draw it

Let's draw it on the grid.

A and B, and the segment between them.

M in the middle.

The bisector goes through M, across A B.

It meets A B at a right angle.

6 Check

Let's check with another point on the line, (8, 9).

Its distance squared to A and to B is the same: 122.

Every point on the bisector is as far from A as from B.

So it is right!

point (8, 9) on the line: to Aยฒ = 122, to Bยฒ = 122

Let's look back.

First: find the midpoint.

Then: slope of AB.

Then: perpendicular slope.

Then: write the equation.

Then: draw it.

Last: check.

Answer
= y = 65x โˆ’ 35

โ–ถ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. perpendicular bisector of (1, 2) and (5, 6)
    Answer
    = y = โˆ’x + 7
  2. perpendicular bisector of (0, 0) and (4, 4)
    Answer
    = y = โˆ’x + 4
  3. perpendicular bisector of (2, 1) and (8, 1)
    Answer
    = x = 5
  4. perpendicular bisector of (3, -2) and (3, 6)
    Answer
    = y = 2
  5. perpendicular bisector of (1, 5) and (5, 1)
    Answer
    = y = x
  6. perpendicular bisector of (-2, 0) and (2, 4)
    Answer
    = y = โˆ’x + 2
  7. perpendicular bisector of (0, 2) and (4, 6)
    Answer
    = y = โˆ’x + 6

Medium

  1. perpendicular bisector of (2, 3) and (6, 1)
    Answer
    = y = 2x โˆ’ 6
  2. perpendicular bisector of (-1, 2) and (3, 10)
    Answer
    = y = โˆ’12x + 132
  3. perpendicular bisector of (0, 1) and (6, 3)
    Answer
    = y = โˆ’3x + 11
  4. perpendicular bisector of (-4, 1) and (2, -1)
    Answer
    = y = 3x + 3
  5. perpendicular bisector of (1, -3) and (5, 5)
    Answer
    = y = โˆ’12x + 52
  6. perpendicular bisector of (-2, -2) and (4, 0)
    Answer
    = y = โˆ’3x + 2
  7. perpendicular bisector of the line joining (2, 7) and (6, -1)
    Answer
    = y = 12x + 1

Harder

  1. perpendicular bisector of (-3, 8) and (9, -2)
    Answer
    = y = 65x โˆ’ 35
  2. perpendicular bisector of (-1, 4) and (5, -4)
    Answer
    = y = 34x โˆ’ 32
  3. perpendicular bisector of (2, -5) and (8, 3)
    Answer
    = y = โˆ’34x + 114
  4. perpendicular bisector of (-6, 1) and (2, 7)
    Answer
    = y = โˆ’43x + 43
  5. perpendicular bisector of (0, -3) and (6, 5)
    Answer
    = y = โˆ’34x + 134
  6. perpendicular bisector of the line joining (-5, 2) and (3, -4)
    Answer
    = y = 43x + 13