Steply

Equation of a circle

Geometry · 24 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Draw the circle
  2. Across and up
  3. Use a² + b² = c²
  4. Check

The steps for Circle center (0, 0) radius 5. Every solution names its steps, so you always know what comes next.

Worked examples

Circle center (0, 0) radius 5 Easy

The question

Question: write the equation of the circle with center (0, 0) and radius 5.

center (0, 0) and radius 5

1 Draw the circle

Draw the grid.

Put the center on the grid: (0, 0).

The radius is 5: go 5 from the center.

Every point 5 away from the center makes the circle.

2 Across and up

Take any point (x, y) on the circle.

Go across: from x = 0 to x is x − 0.

Go up: from y = 0 to y is y − 0.

Across and up make a right angle.

The radius 5 is the longest side.

3 Use a² + b² = c²

The rule for every right triangle: a² + b² = c².

a2 + b2 = c2

Put in a, b and c: (x − 0)² + (y − 0)² = 5².

(x − 0)2 + (y − 0)2 = 52

Taking away 0 changes nothing.

− 0: nothing changes

So it becomes x² + y² = 5².

x2 + y2 = 52

5² means 5 times 5.

That is 25.

52 = 5 × 5 = 25

So the equation is x² + y² = 25.

x2 + y2 = 25

This works for every circle with center (h, k) and radius r.

(x − h)2 + (y − k)2 = r2

4 Check

Let's check with a point on the circle: (5, 0).

Put x = 5 and y = 0 in.

We get 5² + 0².

52 + 02 = 52 + 02

25 plus 0 is 25, the number on the right.

Right!

= 25 + 0 = 25

Let's look back.

First: draw the circle.

Then: across and up.

Then: use a² + b² = c².

Last: check.

Answer
x2 + y2 = 25

▶ Watch it solved

Circle center (2, -3) radius 4 Medium

The question

Question: write the equation of the circle with center (2, −3) and radius 4.

center (2, −3) and radius 4

1 Draw the circle

Draw the grid.

Put the center on the grid: (2, −3).

The radius is 4: go 4 from the center.

Every point 4 away from the center makes the circle.

2 Across and up

Take any point (x, y) on the circle.

Go across: from x = 2 to x is x − 2.

Go up: from y = −3 to y is y − (−3).

Across and up make a right angle.

The radius 4 is the longest side.

3 Use a² + b² = c²

The rule for every right triangle: a² + b² = c².

a2 + b2 = c2

Put in a, b and c: (x − 2)² + (y − (−3))² = 4².

(x − 2)2 + (y − (−3))2 = 42

Taking away a negative is the same as adding.

− (−) = +

So it becomes (x − 2)² + (y + 3)² = 4².

(x − 2)2 + (y + 3)2 = 42

4² means 4 times 4.

That is 16.

42 = 4 × 4 = 16

So the equation is (x − 2)² + (y + 3)² = 16.

(x − 2)2 + (y + 3)2 = 16

Careful: the signs turn.

Center 2 gives x − 2.

center (2, −3) → x − 2, y + 3

This works for every circle with center (h, k) and radius r.

(x − h)2 + (y − k)2 = r2

4 Check

Let's check with a point on the circle: (6, −3).

Put x = 6 and y = −3 in.

We get 4² + 0².

(6 − 2)2 + (−3 + 3)2 = 42 + 02

16 plus 0 is 16, the number on the right.

Right!

= 16 + 0 = 16

Let's look back.

First: draw the circle.

Then: across and up.

Then: use a² + b² = c².

Last: check.

Answer
(x − 2)2 + (y + 3)2 = 16

▶ Watch it solved

Center and radius of x^2 + (y - 5)^2 = 20 Harder

The question

Question: find the center and the radius of x² + (y − 5)² = 20.

x2 + (y − 5)2 = 20

1 Compare with the rule

Every circle has this form: (x − h)² + (y − k)² = r².

The center is (h, k).

The radius is r.

(x − h)2 + (y − k)2 = r2

2 Find the center

x² is the same as (x − 0)²: taking away 0 changes nothing.

x2 = (x − 0)2

So h = 0.

h = 0

y − 5 is like y − k.

So k = 5.

k = 5
y − 5 ↔ y − k

So the center is (0, 5).

center = (0, 5)

3 Find the radius

r² is the number on the right: r² = 20.

r2 = 20

r times r is 20.

So r is the square root of 20.

r = √20

20 is not a square number.

So we keep √20.

That is the exact answer.

4 × 4 = 16, 5 × 5 = 25

With a calculator, √20 is about 4.5, to the nearest tenth.

√20 ≈ 4.5

So the center is (0, 5) and the radius is √20.

center (0, 5) and r = √20

4 Check

Let's check: draw the circle.

Center (0, 5), radius about 4.5.

Put the center on the grid.

Draw the circle around it.

This point is on the circle: (2, 9).

It is 2 across and 4 up from the center.

Put x = 2 and y = 9 in.

We get 2² + 4².

22 + (9 − 5)2 = 22 + 42

4 plus 16 is 20, the number on the right.

Right!

= 4 + 16 = 20

Let's look back.

First: compare with the rule.

Then: find the center.

Then: find the radius.

Last: check.

Answer
center (0, 5) and r = √20

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. circle center (0, 0) radius 5
    Answer
    x2 + y2 = 25
  2. circle center (0, 0) radius 3
    Answer
    x2 + y2 = 9
  3. circle center (2, 3) radius 4
    Answer
    (x − 2)2 + (y − 3)2 = 16
  4. circle center (1, 5) radius 2
    Answer
    (x − 1)2 + (y − 5)2 = 4
  5. circle center (3, 1) radius 6
    Answer
    (x − 3)2 + (y − 1)2 = 36
  6. circle center (4, 2) radius 3
    Answer
    (x − 4)2 + (y − 2)2 = 9
  7. center and radius of x^2 + y^2 = 16
    Answer
    center (0, 0) and r = 4
  8. center and radius of (x - 3)^2 + (y - 2)^2 = 25
    Answer
    center (3, 2) and r = 5
  9. center and radius of (x - 1)^2 + (y - 4)^2 = 9
    Answer
    center (1, 4) and r = 3

Medium

  1. circle center (2, -3) radius 4
    Answer
    (x − 2)2 + (y + 3)2 = 16
  2. circle center (-1, 2) radius 3
    Answer
    (x + 1)2 + (y − 2)2 = 9
  3. circle center (-4, -2) radius 5
    Answer
    (x + 4)2 + (y + 2)2 = 25
  4. circle center (0, -3) radius 2
    Answer
    x2 + (y + 3)2 = 4
  5. circle center (-3, 0) radius 6
    Answer
    (x + 3)2 + y2 = 36
  6. center and radius of (x - 2)^2 + (y + 3)^2 = 16
    Answer
    center (2, −3) and r = 4
  7. center and radius of (x + 1)^2 + (y - 4)^2 = 36
    Answer
    center (−1, 4) and r = 6
  8. center and radius of (x + 5)^2 + (y + 2)^2 = 1
    Answer
    center (−5, −2) and r = 1
  9. center and radius of x^2 + (y - 5)^2 = 9
    Answer
    center (0, 5) and r = 3
  10. center and radius of (x + 2)^2 + y^2 = 49
    Answer
    center (−2, 0) and r = 7

Harder

  1. center and radius of x^2 + (y - 5)^2 = 20
    Answer
    center (0, 5) and r = √20
  2. center and radius of (x - 1)^2 + (y + 2)^2 = 13
    Answer
    center (1, −2) and r = √13
  3. center and radius of (x + 3)^2 + (y - 1)^2 = 8
    Answer
    center (−3, 1) and r = √8
  4. center and radius of (x - 1)^2 + (y - 2)^2 = -4
    Answer
    r2 = −4 impossible
  5. center and radius of (x + 2)^2 + (y - 3)^2 = 0
    Answer
    r = 0