Steply

Rotation about a point

Geometry · 20 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Draw the shape
  2. Turn one point
  3. Find the rule
  4. Turn the other points
  5. Check

The steps for Rotate A(3, 1) B(5, 1) C(3, 4) 90° counterclockwise about (2, 1). Every solution names its steps, so you always know what comes next.

Worked examples

Rotate (4, 3) 180° about (1, 1) Easy

The question

Question: rotate the point P(4, 3) 180° about the point (1, 1).

P = (4, 3)
= 180° about (1, 1)

1 Draw the shape

Put the point on the grid.

The center of the turn is (1, 1).

Everything turns about this point.

2 Turn one point

From the center to P: go right 3

then up 2.

Now turn 180° about the center.

The path from the center turns too.

Right 3 turns into left 3.

Up 2 turns into down 2.

We land on P', (−2, −1).

We call the new point P prime.

The little mark means: the new P.

3 Find the rule

Now the same with numbers, for P.

The turn rules we know turn about the origin.

So first we move the center to the origin: take (1, 1) away from P.

P is (3, 2) from the center.

1. take away the center: (4 − 1, 3 − 1) = (3, 2)

Turn 180°: the rule (x, y) goes to (−x, −y).

(3, 2) becomes (−3, −2).

2. turn: (x, y) → (−x, −y): (3, 2) → (−3, −2)

Then move back: add (1, 1).

We get (−2, −1): P', the same as on the grid!

3. add the center back: (−3 + 1, −2 + 1) = (−2, −1)

Careful!

That is a turn about the origin.

The center here is (1, 1), so we take it away first and add it back at the end.

Careful: not P'(−4, −3) ✗

So the image is P'(−2, −1).

P' = (−2, −1)

4 Check

Let's check P.

Join the center to P

and the center to P'.

From the center, P is (3, 2) away and P' is (−3, −2) away.

Both have length √13: the same distance, as a turn must keep.

center → P: (3, 2), center → P': (−3, −2): both √13 long

And P, the center and P' are on one straight line: a half turn.

Right!

P, center, P': one straight line

Let's look back.

First: draw the shape.

Then: turn one point.

Then: find the rule.

Last: check.

Answer
P' = (−2, −1)

▶ Watch it solved

Rotate A(3, 1) B(5, 1) C(3, 4) 90° counterclockwise about (2, 1) Medium

The question

Question: rotate the shape A(3, 1), B(5, 1) and C(3, 4) 90° counterclockwise about the point (2, 1).

A(3, 1), B(5, 1) and C(3, 4)
= 90° counterclockwise about (2, 1)

1 Draw the shape

Put the points on the grid and join them.

The center of the turn is (2, 1).

Everything turns about this point.

2 Turn one point

Counterclockwise means the other way from the hands of a clock.

counterclockwise = against the clock

From the center to C: go right 1

then up 3.

Now turn 90° counterclockwise about the center.

The path from the center turns too.

Right 1 turns into up 1.

Up 3 turns into left 3.

We land on C', (−1, 2).

We call the new point C prime.

The little mark means: the new C.

3 Find the rule

Now the same with numbers, for C.

The turn rules we know turn about the origin.

So first we move the center to the origin: take (2, 1) away from C.

C is (1, 3) from the center.

1. take away the center: (3 − 2, 4 − 1) = (1, 3)

Turn 90° counterclockwise: the rule (x, y) goes to (−y, x).

(1, 3) becomes (−3, 1).

2. turn: (x, y) → (−y, x): (1, 3) → (−3, 1)

Then move back: add (2, 1).

We get (−1, 2): C', the same as on the grid!

3. add the center back: (−3 + 2, 1 + 1) = (−1, 2)

Careful!

That is a turn about the origin.

The center here is (2, 1), so we take it away first and add it back at the end.

Careful: not C'(−4, 3) ✗

4 Turn the other points

A: take away the center, (1, 0).

Turn: (0, 1).

Add the center back: (2, 2).

A: (1, 0) → (0, 1) → A'(2, 2)

B: take away the center, (3, 0).

Turn: (0, 3).

Add the center back: (2, 4).

B: (3, 0) → (0, 3) → B'(2, 4)

Join the new points.

This new shape is called the image.

So the image is A'(2, 2), B'(2, 4) and C'(−1, 2).

A'(2, 2), B'(2, 4) and C'(−1, 2)

5 Check

Let's check C.

Join the center to C

and the center to C'.

From the center, C is (1, 3) away and C' is (−3, 1) away.

Both have length √10: the same distance, as a turn must keep.

center → C: (1, 3), center → C': (−3, 1): both √10 long

They make a right angle: a quarter turn.

A quarter turn, counterclockwise.

Right!

a right angle at the center: a quarter turn

Let's look back.

First: draw the shape.

Then: turn one point.

Then: find the rule.

Then: turn the other points.

Last: check.

Answer
A'(2, 2), B'(2, 4) and C'(−1, 2)

▶ Watch it solved

Rotate A(1, -1) B(3, -1) C(1, 1) 270° counterclockwise about (-1, -2) Harder

The question

Question: rotate the shape A(1, −1), B(3, −1) and C(1, 1) 270° counterclockwise about the point (−1, −2).

A(1, −1), B(3, −1) and C(1, 1)
= 270° counterclockwise about (−1, −2)

1 Draw the shape

Put the points on the grid and join them.

The center of the turn is (−1, −2).

Everything turns about this point.

2 Turn one point

Counterclockwise means the other way from the hands of a clock.

counterclockwise = against the clock

From the center to A: go right 2

then up 1.

Now turn 270° counterclockwise about the center.

The path from the center turns too.

Right 2 turns into down 2.

Up 1 turns into right 1.

We land on A', (0, −4).

We call the new point A prime.

The little mark means: the new A.

3 Find the rule

Now the same with numbers, for A.

The turn rules we know turn about the origin.

So first we move the center to the origin: take (−1, −2) away from A.

A is (2, 1) from the center.

1. take away the center: (1 − (−1), −1 − (−2)) = (2, 1)

Turn 270° counterclockwise: the rule (x, y) goes to (y, −x).

(2, 1) becomes (1, −2).

2. turn: (x, y) → (y, −x): (2, 1) → (1, −2)

Then move back: add (−1, −2).

We get (0, −4): A', the same as on the grid!

3. add the center back: (1 + (−1), −2 + (−2)) = (0, −4)

Careful!

That is a turn about the origin.

The center here is (−1, −2), so we take it away first and add it back at the end.

Careful: not A'(−1, −1) ✗

4 Turn the other points

B: take away the center, (4, 1).

Turn: (1, −4).

Add the center back: (0, −6).

B: (4, 1) → (1, −4) → B'(0, −6)

C: take away the center, (2, 3).

Turn: (3, −2).

Add the center back: (2, −4).

C: (2, 3) → (3, −2) → C'(2, −4)

Join the new points.

This new shape is called the image.

So the image is A'(0, −4), B'(0, −6) and C'(2, −4).

A'(0, −4), B'(0, −6) and C'(2, −4)

5 Check

Let's check B.

Join the center to B

and the center to B'.

From the center, B is (4, 1) away and B' is (1, −4) away.

Both have length √17: the same distance, as a turn must keep.

center → B: (4, 1), center → B': (1, −4): both √17 long

They make a right angle: a quarter turn.

A quarter turn, clockwise.

Right!

a right angle at the center: a quarter turn

Let's look back.

First: draw the shape.

Then: turn one point.

Then: find the rule.

Then: turn the other points.

Last: check.

Answer
A'(0, −4), B'(0, −6) and C'(2, −4)

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. rotate (4, 3) 180° about (1, 1)
    Answer
    P' = (−2, −1)
  2. rotate (3, 1) 180° about (1, 2)
    Answer
    P' = (−1, 3)
  3. rotate (5, 2) 90° counterclockwise about (2, 2)
    Answer
    P' = (2, 5)
  4. rotate (2, 4) 90° clockwise about (1, 1)
    Answer
    P' = (4, 0)
  5. rotate (0, 3) 180° about (2, 1)
    Answer
    P' = (4, −1)
  6. rotate (-1, 2) 90° counterclockwise about (1, 0)
    Answer
    P' = (−1, −2)
  7. rotate (3, 3) 90° clockwise about (1, 2)
    Answer
    P' = (2, 0)

Medium

  1. rotate A(3, 1) B(5, 1) C(3, 4) 90° counterclockwise about (2, 1)
    Answer
    A'(2, 2), B'(2, 4) and C'(−1, 2)
  2. rotate A(1, 1) B(3, 1) C(3, 2) 180° about (2, 3)
    Answer
    A'(3, 5), B'(1, 5) and C'(1, 4)
  3. rotate A(2, 2) B(4, 2) C(2, 5) 90° clockwise about (1, 1)
    Answer
    A'(2, 0), B'(2, −2) and C'(5, 0)
  4. rotate A(0, 1) B(2, 1) C(2, 3) 90° counterclockwise about (-1, 0)
    Answer
    A'(−2, 1), B'(−2, 3) and C'(−4, 3)
  5. rotate A(1, 2) B(4, 2) C(4, 4) 180° about (1, 0)
    Answer
    A'(1, −2), B'(−2, −2) and C'(−2, −4)
  6. rotate A(2, 0) B(4, 0) C(2, 3) 90° counterclockwise about (1, -1)
    Answer
    A'(0, 0), B'(0, 2) and C'(−3, 0)
  7. rotate A(-1, 1) B(1, 1) C(1, 3) 90° clockwise about (0, -1)
    Answer
    A'(2, 0), B'(2, −2) and C'(4, −2)

Harder

  1. rotate A(1, -1) B(3, -1) C(1, 1) 270° counterclockwise about (-1, -2)
    Answer
    A'(0, −4), B'(0, −6) and C'(2, −4)
  2. rotate A(-2, 1) B(0, 1) C(-2, 2) 90° clockwise about (-1, -1)
    Answer
    A'(1, 0), B'(1, −2) and C'(2, 0)
  3. rotate A(2, 1) B(4, 3) 180° about (-1, 2)
    Answer
    A'(−4, 3) and B'(−6, 1)
  4. rotate A(1, 2) B(3, 2) C(3, 4) 270° clockwise about (2, 0)
    Answer
    A'(0, −1), B'(0, 1) and C'(−2, 1)
  5. rotate A(-3, -1) B(-1, -1) C(-1, 1) 90° counterclockwise about (-2, 1)
    Answer
    A'(0, 0), B'(0, 2) and C'(−2, 2)
  6. rotate A(0, 0) B(2, 0) C(0, 2) 180° about (-1, 1)
    Answer
    A'(−2, 2), B'(−4, 2) and C'(−2, 0)