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Rotate (0, 3) 180° about (2, 1)

Step by step, with the reason for every step · Rotation about a point · Geometry

Step by step

The question

Question: rotate the point P(0, 3) 180° about the point (2, 1).

P = (0, 3)
= 180° about (2, 1)

1 Draw the shape

Put the point on the grid.

The center of the turn is (2, 1).

Everything turns about this point.

2 Turn one point

From the center to P: go left 2

then up 2.

Now turn 180° about the center.

The path from the center turns too.

Left 2 turns into right 2.

Up 2 turns into down 2.

We land on P', (4, −1).

We call the new point P prime.

The little mark means: the new P.

3 Find the rule

Now the same with numbers, for P.

The turn rules we know turn about the origin.

So first we move the center to the origin: take (2, 1) away from P.

P is (−2, 2) from the center.

1. take away the center: (0 − 2, 3 − 1) = (−2, 2)

Turn 180°: the rule (x, y) goes to (−x, −y).

(−2, 2) becomes (2, −2).

2. turn: (x, y) → (−x, −y): (−2, 2) → (2, −2)

Then move back: add (2, 1).

We get (4, −1): P', the same as on the grid!

3. add the center back: (2 + 2, −2 + 1) = (4, −1)

Careful!

That is a turn about the origin.

The center here is (2, 1), so we take it away first and add it back at the end.

Careful: not P'(0, −3) ✗

So the image is P'(4, −1).

P' = (4, −1)

4 Check

Let's check P.

Join the center to P

and the center to P'.

From the center, P is (−2, 2) away and P' is (2, −2) away.

Both have length √8: the same distance, as a turn must keep.

center → P: (−2, 2), center → P': (2, −2): both √8 long

And P, the center and P' are on one straight line: a half turn.

Right!

P, center, P': one straight line

Let's look back.

First: draw the shape.

Then: turn one point.

Then: find the rule.

Last: check.

Answer
P' = (4, −1)

Your turn

Try this one yourself, then check:

P(−1, 1): 180° about (2, 0)
Show the answer
P' = (5, −1)

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