Steply

3x^2 + y^2 = 21, find the slope at (2, 3)

Step by step, with the reason for every step · Implicit differentiation · Calculus

Step by step

The question

Question: find the slope of 3x² + y² = 21 at the point (2, 3).

3x2 + y2 = 21

y is not written alone, but y still depends on x.

So for y we use the chain rule.

y squared gives 2y, times dy/dx.

y depends on x: y2 → 2y × dydx

1 The derivative of each side

Now each term.

x terms as usual, y terms times dy/dx, a number alone gives 0.

6x + 2y dydx = 0

Careful!

y depends on x.

So we must multiply by dy/dx.

Careful: not y2 → 2y ✗

2 Get dy/dx alone

Keep the dy/dx terms on the left.

Move the others to the right: they change sign.

2y dydx = −6x

To remove times 2y, we divide both sides by it.

dydx = −6x2y

Every number on the top and the bottom divides by 2.

top and bottom ÷ 2

Tidy up: dy/dx = −3x over y.

dydx = −3xy

3 The slope at the point

First, is (2, 3) on the curve?

Put x = 2 and y = 3 in.

We get 21.

Yes, it is.

3(2)2 + 32 = 12 + 9 = 21 ✓

Put x = 2 and y = 3 into dy/dx.

dydx = −3(2)3

So the slope at (2, 3) is −2.

= −2

4 Check

Let's check with a very close point on the curve.

At x = 2.001, a calculator gives y ≈ 2.998.

x = 2.001: y ≈ 2.998

The slope between the two points: down 0.002, across 0.001.

About −2.

Very close to −2.

Right!

2.998 − 30.001 ≈ −2

Let's look back.

First: the derivative of each side.

Then: get dy/dx alone.

Then: the slope at the point.

Last: check.

Answer
dydx = −3xy

Your turn

Try this one yourself, then check:

Find the slope of 2x2 + 2y2 = 34
Show the answer
slope = −4

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