Steply

a_1 = 5, a_n = a_(n-1) + 6, find a_6

Step by step, with the reason for every step · Recursive sequences · Algebra 2

Step by step

The question

Question: a₁ = 5 and aₙ = aₙ₋₁ + 6.

Find term 6, a₆.

a1 = 5, an = an−1 + 6

aₙ₋₁ means the term just before aₙ.

A rule that makes each term from the term before is called recursive.

an−1 = the term before an

Careful!

aₙ₋₁ is the term before, not the number n − 1.

For term 2 we put in a₁, which is 5.

Careful: not a2 = 1 + 6 = 7 ✗

1 Start with a₁

The start is given: a₁ = 5.

a1 = 5

2 Use the rule again and again

Term 2: n = 2, so the term before is a₁.

We put in 5.

5 + 6 is 11.

a2 = a1 + 6 = 5 + 6 = 11

Term 3: the term before is a₂, which is 11.

11 + 6 is 17.

a3 = a2 + 6 = 11 + 6 = 17

Term 4: 17 + 6 is 23.

a4 = a3 + 6 = 17 + 6 = 23

Term 5: 23 + 6 is 29.

a5 = a4 + 6 = 23 + 6 = 29

Term 6: 29 + 6 is 35.

a6 = a5 + 6 = 29 + 6 = 35

So a₆ = 35.

3 Check

Let's check by going back.

The rule did plus 6.

Going back, we do the opposite: take away 6.

back: − 6

From 35: 35 − 6 is 29, term 5.

35 − 6 = 29
29 − 6 = 23
23 − 6 = 17
17 − 6 = 11

We land on 5, the start.

It works!

11 − 6 = 5

Let's look back.

First: start with a₁.

Then: use the rule again and again.

Last: check.

Answer
a6 = a5 + 6 = 29 + 6 = 35

Your turn

Try this one yourself, then check:

a1 = 4, an = an−1 + 3, find a6
Show the answer
a6 = 19

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