Steply

a_1 = 64, a_n = a_(n-1) - 9, find the first 4 terms

Step by step, with the reason for every step · Recursive sequences · Algebra 2

Step by step

The question

Question: a₁ = 64 and aₙ = aₙ₋₁ − 9.

Find the first 4 terms.

a1 = 64, an = an−1 − 9

aₙ₋₁ means the term just before aₙ.

A rule that makes each term from the term before is called recursive.

an−1 = the term before an

Careful!

aₙ₋₁ is the term before, not the number n − 1.

For term 2 we put in a₁, which is 64.

Careful: not a2 = 1 − 9 = −8 ✗

1 Start with a₁

The start is given: a₁ = 64.

a1 = 64

2 Use the rule again and again

Term 2: n = 2, so the term before is a₁.

We put in 64.

64 − 9 is 55.

a2 = a1 − 9 = 64 − 9 = 55

Term 3: the term before is a₂, which is 55.

55 − 9 is 46.

a3 = a2 − 9 = 55 − 9 = 46

Term 4: 46 − 9 is 37.

a4 = a3 − 9 = 46 − 9 = 37

3 Write the list

So the first 4 terms are 64, 55, 46, 37.

= 64, 55, 46, 37

4 Check

Let's check by going back.

The rule did minus 9.

Going back, we do the opposite: add 9.

back: + 9

From 37: 37 + 9 is 46, term 3.

37 + 9 = 46
46 + 9 = 55

We land on 64, the start.

It works!

55 + 9 = 64

Let's look back.

First: start with a₁.

Then: use the rule again and again.

Then: write the list.

Last: check.

Answer
= 64, 55, 46, 37

Your turn

Try this one yourself, then check:

a1 = 4, an = an−1 − 1, find the first 4 terms
Show the answer
4, 3, 2, 1

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