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A colony of 500 bacteria grows by 8% every hour. How many bacteria…

Step by step, with the reason for every step · GCSE Maths Higher Paper 3 · GCSE Maths

Step by step

The question

Question: A colony has 500 bacteria and grows 8% each hour.

How many bacteria after 6 hours?

1 Find the start and the factor

The start is 500.

Each hour it keeps all of it, 100%, and gets 8% more.

So it becomes 108% of what it was.

108% is 108/100: 1.08.

That is the factor.

start: a = 500
100% + 8% = 108% = 1.08
factor: b = 1.08

2 Write the rule

x is the number of hours.

Each hour we multiply by 1.08 again.

So y = 500 × 1.08ˣ.

y = 500 × 1.08x

Careful!

The 8% is taken of the NEW amount every hour, not always of 500.

Careful: not 500 + 6 × 40 = 740 ✗

3 Put in x = 6

After 6 hours, x = 6.

y = 500 × 1.086

1.08 to the power 6 is 1.586874.

1.086 = 1.586874

So we multiply 500 by 1.586874.

= 500 × 1.586874

That is 793.437161, about 793.

≈ 793

4 Check

Let's check by going back: 793.437161 divided by 1.08 to the power 6 gives the start, 500.

It works!

793.437161 ÷ 1.086 = 500

Let's look back.

First: find the start and the factor.

Then: write the rule.

Then: put in x = 6.

Last: check.

Answer
≈ 793

Your turn

Try this one yourself, then check your answer:

A colony has 100 bacteria and grows 10% each hour. How many bacteria after 3 hours?
Show the answer
≈ 133

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