Steply

A curve is given by x = t^3 and y = 6t^2. What is dy/dx at t = 2?

Step by step, with the reason for every step · AP Calculus BC Practice Exam 1 · AP Calculus BC

Step by step

The question

Question: find the slope at t = 2, when x = t³ and y = 6t².

x = t3

Both x and y move with a third letter, t, like time.

There are four choices.

First we solve it, the normal way.

Then we pick.

y = 6t2

1 dx/dt and dy/dt

The power rule, with t: dx/dt = 3t².

dxdt = 3t2

And dy/dt = 12t.

dydt = 12t

2 dy/dx

The slope dy over dx is dy over dt, divided by dx over dt: the dt's cancel.

dydx = dydtdxdt

So dy/dx is 12t/(3t²).

dydx = 12t3t2

Simplify: divide the numbers, take away the powers of t.

= 4t

3 At the point

Put in t = 2: dy/dt is 24 and dx/dt is 12.

The slope is 2.

dydx = 2412 = 2
dydt: 12(2) = 24
dxdt: 3(2)2 = 12

Careful!

dy goes on top: dy over dt, divided by dx over dt.

Upside down gives 1/2: wrong.

Careful: not slope = 1224 ✗

So the slope at t = 2 is 2.

slope = 2

Draw the curve: for each t, the point (x, y).

The point at t = 2.

4 Check

Let's check with a calculator: move t a tiny bit around 2, and divide the change in y by the change in x.

About 2: the slope 2 our rule gives.

Right!

t = 2 ± 0.001: ΔyΔx ≈ 2

5 Pick the choice

Our answer is slope = 2.

That is choice D.

D) 2

6 Why not the others

A is 1/2.

Wrong: dx/dt over dy/dt: it is dy/dt over dx/dt.

That is the Careful mistake from before.

A) 12 ✗ dx/dt over dy/dt: it is dy/dt over dx/dt

B is 24.

Wrong: used dy/dt only.

B) 24 ✗ used dy/dt only

C is 4.

Wrong: 4/t: put in t = 2, not t = 1.

C) 4 ✗ 4/t: put in t = 2, not t = 1

Let's look back.

First: dx/dt and dy/dt.

Then: dy/dx.

Then: at the point.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
slope = 2

Your turn

Try this one yourself, then check your answer:

Find the slope at t = 1, when x = t3 and y = 6t²
Show the answer
slope = 4

More from AP Calculus BC Practice Exam 1

The whole lesson: AP Calculus BC Practice Exam 1 →