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A hiker walks 6 km on a bearing of 145°, how far south and how far…

Step by step, with the reason for every step · Bearings with trigonometry and Pythagoras · Geometry

Step by step

The question

Question: a hiker goes 6 km on a bearing of 145°: how far south and how far east is it from the start?

1 Draw the triangle

Go straight south first, then straight east: a right triangle.

The path is the long side.

In the triangle we need the angle at the start, between the path and the south line: 35°.

angle with the north-south line = 180° − 145° = 35°

Careful!

The south side is next to the angle, so it uses cos.

The east side is across from it, so it uses sin.

Careful: south: next to the angle → cos; east: across → sin

2 How far south

cos is adjacent over hypotenuse.

So the south side is 6 times cos 35°: about 4.9 km.

south = 6 × cos 35° ≈ 4.9 km

3 How far east

sin is opposite over hypotenuse.

So the east side is 6 times sin 35°: about 3.4 km.

east = 6 × sin 35° ≈ 3.4 km

4 Check

Let's check with Pythagoras: the two legs squared add up to about 36, the path squared.

So it is right!

4.9² + 3.4² ≈ 35.6 ≈ 6² = 36

Let's look back.

First: draw the triangle.

Then: how far south.

Then: how far east.

Last: check.

Answer
east = 6 × sin 35° ≈ 3.4 km

Your turn

Try this one yourself, then check:

How far south and how far east?
Show the answer
3.5 km south, 3.5 km east

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