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A ship sails 8 km on a bearing of 040°, how far north and how far east

Step by step, with the reason for every step · Bearings with trigonometry and Pythagoras · Geometry

Step by step

The question

Question: a ship goes 8 km on a bearing of 040°: how far north and how far east is it from the start?

1 Draw the triangle

Go straight north first, then straight east: a right triangle.

The path is the long side.

The angle at the start, between north and the path, is the bearing: 40°.

angle at the start = 40°

Careful!

The north side is next to the angle, so it uses cos.

The east side is across from it, so it uses sin.

Careful: north: next to the angle → cos; east: across → sin

2 How far north

cos is adjacent over hypotenuse.

So the north side is 8 times cos 40°: about 6.1 km.

north = 8 × cos 40° ≈ 6.1 km

3 How far east

sin is opposite over hypotenuse.

So the east side is 8 times sin 40°: about 5.1 km.

east = 8 × sin 40° ≈ 5.1 km

4 Check

Let's check with Pythagoras: the two legs squared add up to about 64, the path squared.

So it is right!

6.1² + 5.1² ≈ 63.2 ≈ 8² = 64

Let's look back.

First: draw the triangle.

Then: how far north.

Then: how far east.

Last: check.

Answer
east = 8 × sin 40° ≈ 5.1 km

Your turn

Try this one yourself, then check:

How far north and how far east?
Show the answer
5.8 km north, 6.9 km east

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