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A raffle sells 50 tickets at $4, one prize of $100, expected value

Step by step, with the reason for every step · Expected value · Probability

Step by step

The question

Question: A raffle sells 50 tickets at $4 each.

There is one prize of $100.

What is the expected value of one ticket?

1 Make a table

One row for each outcome: its value and its probability.

Win: the prize is $100, but we paid $4.

So we are up $96.

The chance is 1/50.

Lose: a loss is a negative value, minus 4.

The chance is 49/50.

The chances add up to 1: 1/50 and 49/50 make 50/50.

2 Multiply each row

Win: 96 times 1/50 is 96/50.

96 × 150 = 9650

The expected value: each value times its probability, all added up.

It is what we win or lose per game, on average, if we play many times.

E = expected value:
each value × its probability,
all added

Lose: minus 4 times 49/50 is minus 196/50.

(−4) × 4950 = −19650

3 Add them

Same bottoms: we add the tops.

A loss takes away.

E = 96 − 19650

Careful!

The chances are not equal.

Each value counts as much as its probability.

Careful: not 96 + (−4)2 = 46 ✗

96 minus 196 is minus 100.

E = −10050

Both 100 and 50 can be divided by 50.

That makes it simpler.

E = −100 ÷ 5050 ÷ 50

So the expected value is minus $2.

E = −$2

Negative: in the long run, you lose $2 a ticket.

you lose $2 a ticket on average

4 Check

Let's check.

Imagine 50 tickets.

The chances say: 1 win, 49 lose.

in 50 tickets: 1 win, 49 lose

Together: we are down $100.

1 × $96 − 49 × $4 = −$100

Shared over 50 tickets, that is minus $2 a ticket.

The same.

So the answer is right!

−$100 ÷ 50 = −$2 a ticket

Let's look back.

First: make a table.

Then: multiply each row.

Then: add them.

Last: check.

Answer
E = −$2

Your turn

Try this one yourself, then check:

Show the answer
E = −$5

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