Steply

A random sample of 16 workers takes a mean of 15 minutes to finish a…

Step by step, with the reason for every step · AP Statistics Practice Exam 2 · AP Statistics

Step by step

The question

Question: a sample of 16 has mean 15 and SD 4: find the 90% confidence interval for the true mean.

90% interval for μ: x̄ = 15, s = 4, n = 16

x̄, the sample mean, is 15: the middle of our interval.

s is the SD of the sample: 4.

And n is 16.

x̄: the sample mean, the middle
s: the SD of the sample
n: the sample size

There are four choices.

First we solve it, the normal way.

Then we pick.

1 Why t

We do not know σ, the SD of all the numbers.

We only have s, the SD of the sample.

So we use t instead of z.

σ not known: use s and t

The t curve is a bit wider than the bell, more so for small samples: a small sample makes us less sure.

It makes the interval a bit wider, to be safe.

t: a bit wider than z, to be safe

The t-table has a row for each df, the degrees of freedom: n minus 1.

16 minus 1 is 15.

df = n − 1 = 16 − 1 = 15

2 Find t*

90 percent of the bell is in the middle.

That leaves 10 percent: 5 percent in each end.

90% in the middle: 10% left over, 5% in each end

t* marks the cut between the middle and the ends.

In the t-table we take row 15.

Its columns are named by the middle part: the 90 percent column, which leaves 5 percent in each end.

Row 15, column 90%: t* = 1.753.

t* = 1.753

Careful!

df is n minus 1: 15, not 16.

Careful: not df = 16 ✗

3 Error bound

The error bound: t* times s over the square root of n.

s over the square root of n is the SD of sample means, from the sample means lesson.

t* of those SDs on each side holds the middle part we want.

EBM = t* × s√n

The square root of 16 is 4.

4/4 is 1.

Times 1.753: 1.753.

EBM = 1.753 × 4√16 = 1.753 × 44 = 1.753

4 The interval

Take the error bound away from the middle: 15 minus 1.753 is 13.247.

x̄ − EBM = 15 − 1.753 = 13.247

And add it: 15 plus 1.753 is 16.753.

x̄ + EBM = 15 + 1.753 = 16.753

The 90 percent confidence interval is (13.247, 16.753).

(13.247, 16.753)

5 Say it in words

In words: we are 90 percent confident that the true mean is between 13.247 and 16.753.

90% confident: 13.247 < μ < 16.753

6 Check

Let's check: the middle of the interval should be 15.

13.247 plus 16.753, divided by 2, is 15.

middle: (13.247 + 16.753) ÷ 2 = 15

Half the width should be the error bound: 16.753 minus 13.247, divided by 2, is 1.753.

So it is right!

half the width: (16.753 − 13.247) ÷ 2 = 1.753

7 Pick the choice

Our answer is (13.247, 16.753).

That is choice D.

D) (13.247, 16.753)

8 Why not the others

A is (13.355, 16.645).

Wrong: used z = 1.645: with n = 16 use t = 1.753.

A) (13.355, 16.645) ✗ used z = 1.645: with n = 16 use t = 1.753

B is (13.04, 16.96).

Wrong: used 1.96: that is z for 95%.

B) (13.04, 16.96) ✗ used 1.96: that is z for 95%

C is (7.988, 22.012).

Wrong: used the SD 4 without dividing by √16.

C) (7.988, 22.012) ✗ used the SD 4 without dividing by √16

Let's look back.

First: why t.

Then: find t*.

Then: error bound.

Then: the interval.

Then: say it in words.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
(13.247, 16.753)

Your turn

Try this one yourself, then check your answer:

90% interval for μ: x̄ = 25, s = 4, n = 16
Show the answer
(23.247, 26.753)

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