Steply

A random sample of 25 batteries has mean life 72 hours and standard…

Step by step, with the reason for every step · AP Statistics Practice Exam 2 · AP Statistics

Step by step

The question

Question: a sample of 25 has mean 72 and SD 10: find the 95% confidence interval for the true mean.

95% interval for μ: x̄ = 72, s = 10, n = 25

x̄, the sample mean, is 72: the middle of our interval.

s is the SD of the sample: 10.

And n is 25.

x̄: the sample mean, the middle
s: the SD of the sample
n: the sample size

There are four choices.

First we solve it, the normal way.

Then we pick.

1 Why t

We do not know σ, the SD of all the numbers.

We only have s, the SD of the sample.

So we use t instead of z.

σ not known: use s and t

The t curve is a bit wider than the bell, more so for small samples: a small sample makes us less sure.

It makes the interval a bit wider, to be safe.

t: a bit wider than z, to be safe

The t-table has a row for each df, the degrees of freedom: n minus 1.

25 minus 1 is 24.

df = n − 1 = 25 − 1 = 24

2 Find t*

95 percent of the bell is in the middle.

That leaves 5 percent: 2.5 percent in each end.

95% in the middle: 5% left over, 2.5% in each end

t* marks the cut between the middle and the ends.

In the t-table we take row 24.

Its columns are named by the middle part: the 95 percent column, which leaves 2.5 percent in each end.

Row 24, column 95%: t* = 2.064.

t* = 2.064

Careful!

df is n minus 1: 24, not 25.

Careful: not df = 25 ✗

3 Error bound

The error bound: t* times s over the square root of n.

s over the square root of n is the SD of sample means, from the sample means lesson.

t* of those SDs on each side holds the middle part we want.

EBM = t* × s√n

The square root of 25 is 5.

10/5 is 2.

Times 2.064: 4.128.

EBM = 2.064 × 10√25 = 2.064 × 105 = 4.128

4 The interval

Take the error bound away from the middle: 72 minus 4.128 is 67.872.

x̄ − EBM = 72 − 4.128 = 67.872

And add it: 72 plus 4.128 is 76.128.

x̄ + EBM = 72 + 4.128 = 76.128

The 95 percent confidence interval is (67.872, 76.128).

(67.872, 76.128)

5 Say it in words

In words: we are 95 percent confident that the true mean is between 67.872 and 76.128.

95% confident: 67.872 < μ < 76.128

6 Check

Let's check: the middle of the interval should be 72.

67.872 plus 76.128, divided by 2, is 72.

middle: (67.872 + 76.128) ÷ 2 = 72

Half the width should be the error bound: 76.128 minus 67.872, divided by 2, is 4.128.

So it is right!

half the width: (76.128 − 67.872) ÷ 2 = 4.128

7 Pick the choice

Our answer is (67.872, 76.128).

That is choice D.

D) (67.872, 76.128)

8 Why not the others

A is (68.08, 75.92).

Wrong: used z = 1.96: with a sample SD and n = 25 use t = 2.064.

A) (68.08, 75.92) ✗ used z = 1.96: with a sample SD and n = 25 use t = 2.064

B is (70, 74).

Wrong: used 1 SE.

B) (70, 74) ✗ used 1 SE

C is (51.36, 92.64).

Wrong: used the SD 10 without dividing by √25.

C) (51.36, 92.64) ✗ used the SD 10 without dividing by √25

Let's look back.

First: why t.

Then: find t*.

Then: error bound.

Then: the interval.

Then: say it in words.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
(67.872, 76.128)

Your turn

Try this one yourself, then check your answer:

95% interval for μ: x̄ = 72, s = 5, n = 25
Show the answer
(69.936, 74.064)

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