Steply

A substance has a half-life of 3 days. How much of 64 g is left…

Step by step, with the reason for every step · Half-life and time with logs · Algebra 2

Step by step

The question

Question: A substance has a half-life of 3 days.

How much of 64 g is left after 9 days?

1 Count the half-lives

Every 3 days, half is left.

Half means times 1/2.

every 3 days: × 12

How many half-lives in 9 days?

9 divided by 3: 3.

half-lives = 93 = 3

Careful!

3 half-lives is not divided by 3.

It is halved 3 times, one after another.

Careful: not 64 ÷ 3 = 21.333333 g ✗

2 Halve it that many times

A = the start times (1/2) to the power 3.

A = 64 × (12)3

(1/2) to the power 3 is 1/8.

(12)3 = 18

64 times 1/8 is 64/8.

A = 648

64 divided by 8 is 8 g.

A = 8 g

3 Check

Let's check, half-life by half-life.

Every 3 days, we halve it.

After 9 days we get 8 g again.

It works!

after 9 days: 8 g

Let's look back.

First: count the half-lives.

Then: halve it that many times.

Last: check.

Answer
A = 8 g

Your turn

Try this one yourself, then check:

Show the answer
2 g

More from Half-life and time with logs

The whole lesson: Half-life and time with logs →