Steply

Half-life and time with logs

Algebra 2 · 20 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Write the equation
  2. Get the power alone
  3. Take the log of both sides
  4. Bring the power down
  5. Get t alone
  6. Use a calculator
  7. Check

The steps for $800 is invested at 4% compounded quarterly. How long until it…. Every solution names its steps, so you always know what comes next.

Worked examples

A substance has a half-life of 5 years. How much of 80 g is left… Easy

The question

Question: A substance has a half-life of 5 years.

How much of 80 g is left after 20 years?

1 Count the half-lives

Every 5 years, half is left.

Half means times 1/2.

every 5 years: × 12

How many half-lives in 20 years?

20 divided by 5: 4.

half-lives = 205 = 4

Careful!

4 half-lives is not divided by 4.

It is halved 4 times, one after another.

Careful: not 80 ÷ 4 = 20 g ✗

2 Halve it that many times

A = the start times (1/2) to the power 4.

A = 80 × (12)4

(1/2) to the power 4 is 1/16.

(12)4 = 116

80 times 1/16 is 80/16.

A = 8016

80 divided by 16 is 5 g.

A = 5 g

3 Check

Let's check, half-life by half-life.

Every 5 years, we halve it.

After 20 years we get 5 g again.

It works!

after 20 years: 5 g

Let's look back.

First: count the half-lives.

Then: halve it that many times.

Last: check.

Answer
A = 5 g

▶ Watch it solved

A substance has a half-life of 6 years. How much of 120 g is left… Medium

The question

Question: A substance has a half-life of 6 years.

How much of 120 g is left after 24 years?

1 Count the half-lives

Every 6 years, half is left.

Half means times 1/2.

every 6 years: × 12

How many half-lives in 24 years?

24 divided by 6: 4.

half-lives = 246 = 4

Careful!

4 half-lives is not divided by 4.

It is halved 4 times, one after another.

Careful: not 120 ÷ 4 = 30 g ✗

2 Halve it that many times

A = the start times (1/2) to the power 4.

A = 120 × (12)4

(1/2) to the power 4 is 1/16.

(12)4 = 116

120 times 1/16 is 120/16.

A = 12016

120 divided by 16 is 7.5 g.

A = 7.5 g

3 Check

Let's check, half-life by half-life.

Every 6 years, we halve it.

After 24 years we get 7.5 g again.

It works!

after 24 years: 7.5 g

Let's look back.

First: count the half-lives.

Then: halve it that many times.

Last: check.

Answer
A = 7.5 g

▶ Watch it solved

$800 is invested at 4% compounded quarterly. How long until it… Harder

The question

Question: $800 is invested at 4% compounded quarterly.

How long until it doubles?

1 Write the equation

The compound interest rule, with r/n = 0.04 divided by 4: 0.01.

A = P(1 + rn)nt, 0.04 ÷ 4 = 0.01

We know the start, $800, and the end, $1600.

t is the unknown, up in the power.

800 × 1.014t = 1600

2 Get the power alone

To remove times 800, we divide by 800.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

800 × 1.014t800 = 1600800

800 divided by 800 is 1.

So just the power is left.

1600 divided by 800 is 2.

Now we have 1.01 to the power 4t = 2.

1.014t = 2

Careful!

When the power comes down, all of it comes down: 4t, not just t.

Careful: the whole power 4t comes down, not only t

3 Take the log of both sides

Logs bring a power down.

So we take the log of both sides.

We do it on both sides, so they stay equal.

log(1.014t) = log 2

4 Bring the power down

The power rule for logs: the power comes down in front, as times.

log(aⁿ) = n × log a

The whole power, 4t, comes down in front.

4t × log 1.01 = log 2

5 Get t alone

Divide both sides by 4 times log 1.01.

So t is alone.

t = log 24 × log 1.01

6 Use a calculator

With a calculator: log 2 is about 0.30103.

And log 1.01 is about 0.00432137.

log 2 ≈ 0.30103
log 1.01 ≈ 0.00432137

So t is about 17.42 years, to two decimal places.

t ≈ 17.42

7 Check

Let's check: put t = 17.42 back in.

With a calculator.

We get about $1600.31.

800 × 1.014 × 17.42 ≈ 1600.31

That is 1600, up to the rounding.

It works!

≈ 1600

Let's look back.

First: write the equation.

Then: get the power alone.

Then: take the log of both sides.

Then: bring the power down.

Then: get t alone.

Then: use a calculator.

Last: check.

Answer
t ≈ 17.42

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. A substance has a half-life of 5 years. How much of 80 g is left after 20 years?
    Answer
    A = 5 g
  2. A substance has a half-life of 3 days. How much of 64 g is left after 9 days?
    Answer
    A = 8 g
  3. A substance has a half-life of 10 years. How much of 200 mg is left after 30 years?
    Answer
    A = 25 mg
  4. A substance has a half-life of 2 hours. How much of 48 g is left after 8 hours?
    Answer
    A = 3 g
  5. A substance has a half-life of 5 years. How long until 80 g decays to 10 g?
    Answer
    Careful: not t = 3 years ✗
  6. A substance has a half-life of 4 days. How long until 96 g decays to 12 g?
    Answer
    Careful: not t = 3 days ✗
  7. A substance has a half-life of 6 hours. How long until 40 mg decays to 5 mg?
    Answer
    Careful: not t = 3 hours ✗

Medium

  1. A substance has a half-life of 6 years. How much of 120 g is left after 24 years?
    Answer
    A = 7.5 g
  2. A substance has a half-life of 5 years. How much of 80 g is left after 12 years?
    Answer
    A ≈ 15.16 g
  3. A substance has a half-life of 8 days. How much of 50 mg is left after 20 days?
    Answer
    A ≈ 8.84 mg
  4. $500 grows by 4% a year. How many years until it is $800?
    Answer
    t ≈ 11.98
  5. $1000 is invested at 5% compounded continuously. How long until it doubles?
    Answer
    t ≈ 13.86
  6. How long until $1000 invested at 6% compounded monthly grows to $2000?
    Answer
    t ≈ 11.58
  7. A substance has a half-life of 5 years. How long until 80 g decays to 30 g?
    Answer
    t ≈ 7.08
  8. $2000 grows by 3% a year. How many years until it is $2600?
    Answer
    t ≈ 8.88

Harder

  1. $800 is invested at 4% compounded quarterly. How long until it doubles?
    Answer
    t ≈ 17.42
  2. $1500 is invested at 6% compounded continuously. How long until it triples?
    Answer
    t ≈ 18.31
  3. A substance has a half-life of 10 days. How long until 60 mg decays to 20 mg?
    Answer
    t ≈ 15.85
  4. How long until $3000 invested at 5% compounded monthly grows to $4500?
    Answer
    t ≈ 8.13
  5. A substance has a half-life of 3 years. How much of 90 g is left after 10 years?
    Answer
    A ≈ 8.93 g