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Angle between <1, 2, 2> and <2, 1, -2>

Step by step, with the reason for every step · Dot product and angle in space · Calculus 3

Step by step

The question

Question: find the angle between u = ⟨1, 2, 2⟩ and v = ⟨2, 1, −2⟩.

u = ⟨1, 2, 2⟩ and v = ⟨2, 1, −2⟩

1 Find u • v

Multiply the matching parts: x times x, y times y, z times z.

Then add.

u • v = 1 × 2 + 2 × 1 + 2 × (−2)

1 times 2 is 2.

2 times 1 is 2.

2 times (−2) is −4.

u • v = 2 + 2 − 4

Add them up: u • v = 0.

u • v = 0

2 The two lengths

The length of u: square the parts and add.

1 plus 4 plus 4 is 9.

The square root is 3.

‖u‖ = √12 + 22 + 22 = √9 = 3

The length of v: square the parts and add.

4 plus 1 plus 4 is 9.

The square root is 3.

‖v‖ = √22 + 12 + (−2)2 = √9 = 3

3 Find the angle

The rule: cos θ is the dot product over the two lengths multiplied.

cos θ = u • v‖u‖ × ‖v‖

Put in u • v = 0 and the two lengths.

cos θ = 03 × 3

0/9 is the same as 0.

cos θ = 0

4 Find θ

The cos⁻¹ button turns it back into the angle.

θ = cos−1(0)

Careful!

That number is cos θ, not the angle.

We still need cos⁻¹.

Careful: not θ = 0 ✗

The calculator gives exactly 90.

So θ = 90°.

θ = 90°

5 Check

A dot product of 0 always means 90°.

It fits!

u • v = 0 → θ = 90°

And cos of 90° is about 0, the same number we had.

Right!

cos 90° ≈ 0

Let's look back.

First: find u • v.

Then: the two lengths.

Then: find the angle.

Then: find θ.

Last: check.

Answer
θ = 90°

Your turn

Try this one yourself, then check:

angle between ⟨1, 2, 2⟩ and ⟨4, 2, −4⟩
Show the answer
θ = 90°

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