Steply

Angle between <2, 2, 1> and <1, 2, 2>

Step by step, with the reason for every step · Dot product and angle in space · Calculus 3

Step by step

The question

Question: find the angle between u = ⟨2, 2, 1⟩ and v = ⟨1, 2, 2⟩.

u = ⟨2, 2, 1⟩ and v = ⟨1, 2, 2⟩

1 Find u • v

Multiply the matching parts: x times x, y times y, z times z.

Then add.

u • v = 2 × 1 + 2 × 2 + 1 × 2

2 times 1 is 2.

2 times 2 is 4.

1 times 2 is 2.

u • v = 2 + 4 + 2

Add them up: u • v = 8.

u • v = 8

2 The two lengths

The length of u: square the parts and add.

4 plus 4 plus 1 is 9.

The square root is 3.

‖u‖ = √22 + 22 + 12 = √9 = 3

The length of v: square the parts and add.

1 plus 4 plus 4 is 9.

The square root is 3.

‖v‖ = √12 + 22 + 22 = √9 = 3

3 Find the angle

The rule: cos θ is the dot product over the two lengths multiplied.

cos θ = u • v‖u‖ × ‖v‖

Put in u • v = 8 and the two lengths.

cos θ = 83 × 3

So cos θ = 8/9.

cos θ = 89

4 Find θ

The cos⁻¹ button turns it back into the angle.

θ = cos−1(89)

Careful!

That number is cos θ, not the angle.

We still need cos⁻¹.

Careful: not θ = 8/9 ✗

The calculator gives about 27.266.

To the nearest tenth, θ ≈ 27.3°.

θ ≈ 27.3°

5 Check

The dot product is positive, so θ is less than 90°.

27.3° fits!

u • v > 0 → θ < 90°

And cos of 27.3° is about 0.889, the same number we had.

Right!

cos 27.3° ≈ 0.889

Let's look back.

First: find u • v.

Then: the two lengths.

Then: find the angle.

Then: find θ.

Last: check.

Answer
θ ≈ 27.3°

Your turn

Try this one yourself, then check:

angle between ⟨3, 1, 1⟩ and ⟨1, 1, 3⟩
Show the answer
θ ≈ 50.5°

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