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Area between y = -x^2 + 4x and the x-axis

Step by step, with the reason for every step · Definite integrals and area · Calculus

Step by step

The question

Question: find the area between y = −x² + 4x and the x-axis.

y = −x2 + 4x

1 Draw the region

Draw the curve first.

Where does it cross the x-axis?

Where y is 0.

−x² + 4x = 0

Factor it.

We need two numbers that multiply to 0 and add to −4: 0 and −4.

−x(x − 4) = 0

So it crosses at x = 0 and x = 4.

x = 0 or x = 4

The area we want is shaded: under the curve, above the x-axis, from 0 to 4.

This area is the integral from 0 to 4.

area = ∫ from 0 to 4 of (−x2 + 4x) dx

2 The antiderivative

First the antiderivative: add 1 to each power, divide by the new power.

F(x) = −x33 + 4 × x22

Now we have F(x) = −x³ over 3 + 2 x².

= −x33 + 2x2

No + C here: in F(b) minus F(a), the two Cs cancel.

no + C here: it cancels

3 Top minus bottom

The rule: put in the top number, then take away the bottom number.

∫ from a to b of f(x) dx = F(b) − F(a)

Write F(x) with 0 and 4 on the bar.

= (−x33 + 2x2) from 0 to 4

Put in 4 first, then take away the same with 0.

= (−433 + 2(4)2) − (−033 + 2(0)2)

Work out each bracket.

= 323 − 0

Careful!

Top first, then take away the bottom.

The other way gives the wrong sign.

Careful: not F(0) − F(4) ✗

So the area is 32/3 square units.

area = 323 square units

4 Check

Let's check F: its derivative is − x² + 4x, the function we started with.

Right!

F′(x) = −x2 + 4x

Let's look back.

First: draw the region.

Then: the antiderivative.

Then: top minus bottom.

Last: check.

Answer
area = 323 square units

Your turn

Try this one yourself, then check:

Find the area between y = 3 − 3x2
Show the answer
area = 4 square units

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