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Area inside r = 2 + 2cos θ

Step by step, with the reason for every step · Area in polar coordinates · Calculus 2

Step by step

The question

Question: find the area inside the curve r = 2 + 2cos θ.

r = 2 + 2cos θ

1 Draw it

A polar grid: circles around the center, and a line for each angle.

For each angle θ, go out a distance r.

The curve closes up.

2 One trip around

The curve goes around once as θ goes from 0 to 2π.

θ from 0 to 2π

3 Write the integral

Cut the area into thin slices from the center.

Each is almost a thin triangle: one half r squared dθ, like a slice of a circle.

slice ≈ 12r2 dθ

Add up the slices: A is one half of the integral of r squared.

A = 12∫ from 0 to 2π of (2 + 2cos θ)2 dθ

Careful!

Do not forget the one half!

A slice is half of r squared dθ.

Careful: not A = ∫ r2 dθ ✗

4 Square it

Square the bracket: first squared, two times first times second, second squared.

A = 12∫ from 0 to 2π of (4 + 8cos θ + 4cos2 θ) dθ

5 Use the half-angle rule

The half-angle rule: cos squared is 1 plus cos of double the angle, over 2.

cos2 θ = 1 + cos 2θ2

Use it, then add the plain numbers: 4 plus 2 is 6.

= 12∫ from 0 to 2π of (6 + 8cos θ + 2 cos 2θ) dθ

6 Integrate

Integrate: a number gives the number times θ.

cos gives sin, divided by the number in front of θ; sin gives minus cos.

A = 12[ 6θ + 8sin θ + sin 2θ ] from 0 to 2π

7 Top minus bottom

Every sin part is 0 at these limits: sin of a whole number of half turns is 0.

sin 0 = sin π = sin 2π = 0

Only the θ part is left: 6 times the length of the interval, 2π.

= 12 × 6 × (2π − 0)

So the area is 6π square units, about 18.85.

A = 6π ≈ 18.85

8 Check

Let's check with a calculator: it adds up 1000 thin slices.

That gives about 18.85, the same as our answer.

Right!

1000 thin slices: ≈ 18.85

Let's look back.

First: draw it.

Then: one trip around.

Then: write the integral.

Then: square it.

Then: use the half-angle rule.

Then: integrate.

Then: top minus bottom.

Last: check.

Answer
A = 6π ≈ 18.85

Your turn

Try this one yourself, then check:

Find the area inside the curve r = 3 + 2cos θ
Show the answer
A = 11π

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