Steply

Area inside r = 5

Step by step, with the reason for every step · Area in polar coordinates · Calculus 2

Step by step

The question

Question: find the area inside the curve r = 5.

r = 5

1 Draw it

A polar grid: circles around the center, and a line for each angle.

For each angle θ, go out a distance r.

The curve closes up.

2 One trip around

A circle around the center: once around is θ from 0 to 2π.

θ from 0 to 2π

3 Write the integral

Cut the area into thin slices from the center.

Each is almost a thin triangle: one half r squared dθ, like a slice of a circle.

slice ≈ 12r2 dθ

Add up the slices: A is one half of the integral of r squared.

A = 12∫ from 0 to 2π of (5)2 dθ

Careful!

Do not forget the one half!

A slice is half of r squared dθ.

Careful: not A = ∫ r2 dθ ✗

4 Square it

Square r.

A = 12∫ from 0 to 2π of (25) dθ

5 Integrate

Integrate: a number gives the number times θ.

cos gives sin, divided by the number in front of θ.

A = 12[ 25θ ] from 0 to 2π

6 Top minus bottom

Every sin part is 0 at these limits: sin of a whole number of half turns is 0.

sin 0 = sin π = sin 2π = 0

Only the θ part is left: 25 times the length of the interval, 2π.

= 12 × 25 × (2π − 0)

So the area is 25π square units, about 78.54.

A = 25π ≈ 78.54

7 Check

Let's check: the curve is a circle, radius 5.

π r squared gives 25π.

The same.

Right!

circle, radius 5: π × (5)² = 25π

Let's look back.

First: draw it.

Then: one trip around.

Then: write the integral.

Then: square it.

Then: integrate.

Then: top minus bottom.

Last: check.

Answer
A = 25π ≈ 78.54

Your turn

Try this one yourself, then check:

Find the area inside the curve r = 6
Show the answer
A = 36π

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