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Asymptotes of f(x) = 3/(x + 1)

Step by step, with the reason for every step · Rational functions · Algebra 2

Step by step

The question

Question: find the asymptotes and holes of f(x) = 3/(x + 1).

f(x) = 3x + 1

An asymptote is a line the graph gets closer and closer to, but never reaches.

We draw it dashed.

asymptote: a line the graph gets close to, but never reaches

1 Vertical asymptotes

We can never divide by 0.

Where the bottom is 0, the graph shoots up or down.

÷ 0: not allowed

The bottom: x + 1 = 0 when x = −1.

x + 1 = 0 → x = −1

Look: at x = −0.9, the bottom is tiny.

So f(x) is about 30: huge.

x = −0.9: bottom 0.1, f(x) ≈ 30

2 Horizontal asymptote

For a very big x, the biggest power on the top and on the bottom is all that counts.

The rest is tiny next to it.

a big x: only the biggest powers count

The top has a smaller power than the bottom.

When x is huge, the bottom is much bigger, so f(x) gets close to 0.

f(x) ≈ 3x

Look: at x = 100, f(x) is about 0.03.

Close to 0.

x = 100: f(100) ≈ 0.03

So the horizontal asymptote is y = 0.

y = 0

So: x = −1 and y = 0.

= x = −1, y = 0

3 Check

Let's check: put x = −1 in the question's bottom.

It gives 0.

Dividing by 0 is not allowed: an asymptote.

x = −1: bottom = 0 ÷ 0

And a very big x, 1000, gives almost exactly 0.

It works!

x = 1000: f(1000) ≈ 0.003 close to 0

Let's look back.

First: vertical asymptotes.

Then: horizontal asymptote.

Last: check.

Answer
= x = −1, y = 0

Your turn

Try this one yourself, then check:

asymptotes of f(x) = 3x + 3
Show the answer
x = −3, y = 0

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