Steply

Asymptotes of f(x) = (x - 1)/((x - 1)(x + 2))

Step by step, with the reason for every step · Rational functions · Algebra 2

Step by step

The question

Question: find the asymptotes and holes of f(x) = (x − 1)/(x − 1)(x + 2).

f(x) = x − 1(x − 1)(x + 2)

An asymptote is a line the graph gets closer and closer to, but never reaches.

We draw it dashed.

asymptote: a line the graph gets close to, but never reaches

1 Find the holes

Now look for the same bracket on the top and the bottom.

f(x) = (x − 1)(x − 1)(x + 2)

(x − 1) is on the top and the bottom.

(x − 1)/(x − 1) is 1.

Cross them out.

What is left: 1/(x + 2).

f(x) = 1x + 2

But the x that made the crossed bracket 0 is still not allowed in the question.

The graph just has one missing point there: a hole.

crossed out → a hole (one missing point)

Careful!

A crossed-out bracket gives a hole, not an asymptote.

The graph only misses one point there.

Careful: not x = 1 is an asymptote ✗

Put x = 1 into what is left: y is 1/3.

So the hole is at (1, 1/3).

= hole: x = 1, y = 13

2 Vertical asymptotes

We can never divide by 0.

Where the bottom is 0, the graph shoots up or down.

÷ 0: not allowed

What is left at the bottom: x + 2 = 0 when x = −2.

x + 2 = 0 → x = −2

Look: at x = −1.9, the bottom is tiny.

So f(x) is about 10: huge.

x = −1.9: bottom 0.1, f(x) ≈ 10

3 Horizontal asymptote

For a very big x, the biggest power on the top and on the bottom is all that counts.

The rest is tiny next to it.

a big x: only the biggest powers count

The top has a smaller power than the bottom.

When x is huge, the bottom is much bigger, so f(x) gets close to 0.

f(x) ≈ xx2

Look: at x = 100, f(x) is about 0.01.

Close to 0.

x = 100: f(100) ≈ 0.01

So the horizontal asymptote is y = 0.

y = 0

So: hole (1, 1/3), x = −2 and y = 0.

= hole (1, 13), x = −2, y = 0

4 Check

Let's check: put x = −2 in the question's bottom.

It gives 0.

Dividing by 0 is not allowed: an asymptote.

x = −2: bottom = 0 ÷ 0

And a very big x, 1000, gives almost exactly 0.

It works!

x = 1000: f(1000) ≈ 0.001 close to 0

Let's look back.

First: find the holes.

Then: vertical asymptotes.

Then: horizontal asymptote.

Last: check.

Answer
= hole (1, 13), x = −2, y = 0

Your turn

Try this one yourself, then check:

asymptotes of f(x) = x − 2(x − 2)(x + 1)
Show the answer
hole (2, 13), x = −1, y = 0

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