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Calculate 4, 12, 36, ..., sum of the first 5 terms

Step by step, with the reason for every step · Sequences · Algebra 2

Step by step

The question

Question: 4, 12, 36, …: find the sum of the first 5 terms.

A sequence is a list of numbers in order.

4, 12, 36, ...

1 Find the ratio

We multiply by 3 every time.

A list like this is a geometric sequence.

The number we multiply by is called the ratio: r = 3.

r = 3

2 Write S and 3S

S is the sum: all 5 terms added.

Now times 3: each term times 3 is the next term.

So the sum moves one place to the right.

3 Take away

We take S away from 3S.

The terms in the middle are in both rows.

They cross out.

Only 972 and 4 are left.

3S − S = 972 − 4

3S take away S is 2S.

972 − 4 is 968.

2S = 968

To remove times 2, we divide by 2.

S = 9682

So the sum of the first 5 terms is 484.

S5 = 484

This works for every geometric sequence: the first term, times r to the power n, minus 1, over r minus 1.

Sn = a1(rn − 1)r − 1

4 Check

Let's check: add the 5 terms one by one.

Add: 4 + 12 + 36 + 108 + 324 = 484

We get 484 again.

So the sum is right!

Let's look back.

First: find the ratio.

Then: write S and 3S.

Then: take away.

Last: check.

Answer
S5 = 484

Your turn

Try this one yourself, then check:

1, 3, 9, ... find S5
Show the answer
S5 = 121

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