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Calculate 75th percentile, mean 500, sd 100

Step by step, with the reason for every step · Normal cut-offs · University Statistics

Step by step

The question

Question: X is normal, with mean 500 and SD 100: which value has 75% below it?

μ = 500, σ = 100: x with 75% below it?

A value with 75 percent below it is also called the 75th percentile.

75% below it = the 75th percentile

1 Shade the area

The bell, with the mean 500 in the middle.

x is the cut-off we want.

75 percent is below x: we shade it, on the left of x.

2 Area to the left

The z-table works with the area to the left of z.

z-table: area to the left of z

75 percent is 0.75.

It is already on the left.

area to the left = 0.75

Careful!

More than half the bell is on the left.

So x is above the mean, and z is positive.

Careful: more than half on the left: z is positive

3 Find it inside the table

Now we look for 0.7500 inside the table.

The closest number is 0.7486: row 0.6, column .07.

So z is about 0.67.

4 Back to x

Start at the mean, then go z SDs: x is the mean plus z times the SD.

x = μ + z × σ

0.67 times 100 is 67.

500 plus 67 is 567.

x = 500 + 0.67 × 100 = 500 + 67 = 567

5 Check

Let's check: the z of 567 is 567 minus 500, over 100.

That is 0.67.

z = 567 − 500100 = 0.67

The table at 0.67 gives 0.7486: about 0.75 to the left.

So it is right!

table at z = 0.67: 0.7486 ≈ 0.75

Let's look back.

First: shade the area.

Then: area to the left.

Then: find it inside the table.

Then: back to x.

Last: check.

Answer
x = 500 + 0.67 × 100 = 500 + 67 = 567

Your turn

Try this one yourself, then check:

μ = 490, σ = 200: x with 75% below it?
Show the answer
x = 624

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