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Calculate 95% confidence interval: mean 1.024, sd 0.2, n 25

Step by step, with the reason for every step · Confidence interval for a mean · University Statistics

Step by step

The question

Question: a sample of 25 has mean 1.024, and the SD of all the numbers is 0.2: find the 95% confidence interval for the true mean.

95% interval for μ: x̄ = 1.024, σ = 0.2, n = 25

x̄, the sample mean, is 1.024: the middle of our interval.

σ, the SD of all the numbers, is known: 0.2.

And n, the sample size, is 25.

x̄: the sample mean, the middle
σ: the SD of all the numbers (known)
n: the sample size

The interval goes from the sample mean minus the error bound, EBM, to the sample mean plus the error bound.

interval = x̄ − EBM to x̄ + EBM

1 Find z*

95 percent of the bell is in the middle.

That leaves 5 percent: 2.5 percent in each end.

95% in the middle: 5% left over, 2.5% in each end

z* marks the cut between the middle and the ends.

Left of z* are the middle and one end: 0.95 plus 0.025 is 0.9750.

left of z* = 0.95 + 0.025 = 0.9750

Now we look for 0.9750 inside the table.

0.9750 is in the table: row 1.9, column .06.

So z = 1.96.

z* = 1.96

2 Error bound

The error bound: z* times σ over the square root of n.

EBM = z* × σ√n

The square root of 25 is 5.

0.2/5 is 0.04.

Times 1.96: 0.0784.

EBM = 1.96 × 0.2√25 = 1.96 × 0.25 = 0.0784

Careful!

We divide by the square root of 25, not by 25.

Careful: not 0.225 ✗

3 The interval

Take the error bound away from the middle: 1.024 minus 0.0784 is 0.9456.

= x̄ − EBM = 1.024 − 0.0784 = 0.9456

And add it: 1.024 plus 0.0784 is 1.1024.

= x̄ + EBM = 1.024 + 0.0784 = 1.1024

The 95 percent confidence interval is (0.9456, 1.1024).

= (0.9456, 1.1024)

4 Say it in words

In words: we are 95 percent confident that the true mean is between 0.9456 and 1.1024.

95% confident: 0.9456 < μ < 1.1024

5 Check

Let's check: the middle of the interval should be 1.024.

0.9456 plus 1.1024, divided by 2, is 1.024.

middle: (0.9456 + 1.1024) ÷ 2 = 1.024

Half the width should be the error bound: 1.1024 minus 0.9456, divided by 2, is 0.0784.

So it is right!

half the width: (1.1024 − 0.9456) ÷ 2 = 0.0784

Let's look back.

First: find z*.

Then: error bound.

Then: the interval.

Then: say it in words.

Last: check.

Answer
= (0.9456, 1.1024)

Your turn

Try this one yourself, then check:

95% interval for μ: x̄ = 5.024, σ = 0.6, n = 25
Show the answer
(4.7888, 5.2592)

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