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Calculate 99th percentile, mean 100, sd 15

Step by step, with the reason for every step · Normal cut-offs · University Statistics

Step by step

The question

Question: X is normal, with mean 100 and SD 15: which value has 99% below it?

μ = 100, σ = 15: x with 99% below it?

A value with 99 percent below it is also called the 99th percentile.

99% below it = the 99th percentile

1 Shade the area

The bell, with the mean 100 in the middle.

x is the cut-off we want.

99 percent is below x: we shade it, on the left of x.

2 Area to the left

The z-table works with the area to the left of z.

z-table: area to the left of z

99 percent is 0.99.

It is already on the left.

area to the left = 0.99

Careful!

More than half the bell is on the left.

So x is above the mean, and z is positive.

Careful: more than half on the left: z is positive

3 Find it inside the table

Now we look for 0.9900 inside the table.

The closest number is 0.9901: row 2.3, column .03.

So z is about 2.33.

4 Back to x

Start at the mean, then go z SDs: x is the mean plus z times the SD.

x = μ + z × σ

2.33 times 15 is 34.95.

100 plus 34.95 is 134.95.

x = 100 + 2.33 × 15 = 100 + 34.95 = 134.95

5 Check

Let's check: the z of 134.95 is 134.95 minus 100, over 15.

That is 2.33.

z = 134.95 − 10015 = 2.33

The table at 2.33 gives 0.9901: about 0.99 to the left.

So it is right!

table at z = 2.33: 0.9901 ≈ 0.99

Let's look back.

First: shade the area.

Then: area to the left.

Then: find it inside the table.

Then: back to x.

Last: check.

Answer
x = 100 + 2.33 × 15 = 100 + 34.95 = 134.95

Your turn

Try this one yourself, then check:

μ = 70, σ = 45: x with 99% below it?
Show the answer
x = 174.85

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