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Calculate arccos(-√3/2)

Step by step, with the reason for every step · Inverse trig values · Trigonometry

Step by step

The question

Question: find cos⁻¹(−√3/2).

cos−1(−√32) = ?

1 What it asks

cos⁻¹ of −√3/2 means: the angle whose cosine is −√3/2.

We call that angle θ.

So cos θ = −√3/2.

cos θ = −√32

2 The allowed range

Many angles have a cosine of −√3/2.

Going round, there are many.

The cos⁻¹ button must give just one.

So cos⁻¹ only gives angles from 0° to 180°: the top half of the circle.

There, every cosine from −1 to 1 happens just once.

0° ≤ θ ≤ 180°

3 Find the angle

From the unit circle: cos 30° = √3/2.

Without the minus, the angle is 30°.

cos 30° = √32

Careful!

cos⁻¹ never gives a negative angle: its range is the top half.

And cos −30° is plus √3/2, not minus.

Careful: not θ = −30° ✗

Cos is the across value.

Minus means left of the y-axis.

In the top half, that is the top left: 180° − 30°.

θ = 180° − 30°

So θ = 150°.

θ = 150°

4 In radians

In radians: 150 times π over 180.

That is 5π/6.

θ = 150 × π180 = 5π6

So cos⁻¹(−√3/2) = 150° = 5π/6.

cos−1(−√32) = 150° = 5π6

5 Check

Let's check: cos 150° is −√3/2.

cos 150° = −√32

And 150° is inside the range.

So it is right!

0° ≤ 150° ≤ 180°

Let's look back.

First: what it asks.

Then: the allowed range.

Then: find the angle.

Then: in radians.

Last: check.

Answer
cos−1(−√32) = 150° = 5π6

Your turn

Try this one yourself, then check:

cos−1(−12) = ?
Show the answer
cos−1(−12) = 120° = 2π3

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