Worked examples
The question
Question: find sin⁻¹(1/2).
sin−1(12) = ?
1 What it asks
sin⁻¹ of 1/2 means: the angle whose sine is 1/2.
We call that angle θ.
So sin θ = 1/2.
sin θ = 12
2 The allowed range
Many angles have a sine of 1/2.
150° and 390° work too.
The sin⁻¹ button must give just one.
So sin⁻¹ only gives angles from −90° to 90°: the right half of the circle.
There, every sine from −1 to 1 happens just once.
−90° ≤ θ ≤ 90°
3 Find the angle
From the unit circle: sin 30° = 1/2.
sin 30° = 12
Careful!
Other angles have the same sin, like 150°.
But only 30° is in the range.
So the button gives 30°.
Careful: only the angle in the range
30° is in the range.
So θ = 30°.
θ = 30°
4 In radians
In radians: 30 times π over 180.
That is π/6.
θ = 30 × π180 = π6
So sin⁻¹(1/2) = 30° = π/6.
sin−1(12) = 30° = π6
5 Check
Let's check: sin 30° is 1/2.
sin 30° = 12
And 30° is inside the range.
So it is right!
−90° ≤ 30° ≤ 90°
Let's look back.
First: what it asks.
Then: the allowed range.
Then: find the angle.
Then: in radians.
Last: check.
Answer sin−1(12) = 30° = π6
▶ Watch it solved
The question
Question: find sin⁻¹(−1/2).
sin−1(−12) = ?
1 What it asks
sin⁻¹ of −1/2 means: the angle whose sine is −1/2.
We call that angle θ.
So sin θ = −1/2.
sin θ = −12
2 The allowed range
Many angles have a sine of −1/2.
Going round, there are many.
The sin⁻¹ button must give just one.
So sin⁻¹ only gives angles from −90° to 90°: the right half of the circle.
There, every sine from −1 to 1 happens just once.
−90° ≤ θ ≤ 90°
3 Find the angle
From the unit circle: sin 30° = 1/2.
Without the minus, the angle is 30°.
sin 30° = 12
Careful!
330° has the right sin, but it is not between −90° and 90°.
Below the x-axis on the right, inside the range, is −30°.
Careful: not θ = 330° ✗
Sin is the up value.
Minus means below the x-axis.
In the right half, that is turning 30° the other way: θ = −30°.
θ = −30°
4 In radians
In radians: −30 times π over 180.
That is −π/6.
θ = −30 × π180 = −π6
So sin⁻¹(−1/2) = −30° = −π/6.
sin−1(−12) = −30° = −π6
5 Check
Let's check: sin −30° is −1/2.
sin −30° = −12
And −30° is inside the range.
So it is right!
−90° ≤ −30° ≤ 90°
Let's look back.
First: what it asks.
Then: the allowed range.
Then: find the angle.
Then: in radians.
Last: check.
Answer sin−1(−12) = −30° = −π6
▶ Watch it solved
The question
Question: find sin⁻¹(√3/2).
Give the angle in degrees.
sin−1(√32) = ?
1 What it asks
sin⁻¹ of √3/2 means: the angle whose sine is √3/2.
We call that angle θ.
So sin θ = √3/2.
sin θ = √32
2 The allowed range
Many angles have a sine of √3/2.
120° and 420° work too.
The sin⁻¹ button must give just one.
So sin⁻¹ only gives angles from −90° to 90°: the right half of the circle.
There, every sine from −1 to 1 happens just once.
−90° ≤ θ ≤ 90°
3 Find the angle
From the unit circle: sin 60° = √3/2.
sin 60° = √32
Careful!
Other angles have the same sin, like 120°.
But only 60° is in the range.
So the button gives 60°.
Careful: only the angle in the range
60° is in the range.
So θ = 60°.
θ = 60°
So sin⁻¹(√3/2) = 60°.
sin−1(√32) = 60°
4 Check
Let's check: sin 60° is √3/2.
sin 60° = √32
And 60° is inside the range.
So it is right!
−90° ≤ 60° ≤ 90°
Let's look back.
First: what it asks.
Then: the allowed range.
Then: find the angle.
Last: check.
▶ Watch it solved