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Center and radius of x^2 + y^2 = 16

Step by step, with the reason for every step · Equation of a circle · Geometry

Step by step

The question

Question: find the center and the radius of x² + y² = 16.

x2 + y2 = 16

1 Compare with the rule

Every circle has this form: (x − h)² + (y − k)² = r².

The center is (h, k).

The radius is r.

(x − h)2 + (y − k)2 = r2

2 Find the center

x² is the same as (x − 0)²: taking away 0 changes nothing.

x2 = (x − 0)2

So h = 0.

h = 0

y² is the same as (y − 0)²: taking away 0 changes nothing.

y2 = (y − 0)2

So k = 0.

k = 0

So the center is (0, 0).

center = (0, 0)

3 Find the radius

r² is the number on the right: r² = 16.

r2 = 16

r times r is 16.

So r is the square root of 16.

r = √16

4 times 4 is 16.

4 × 4 = 16

So r = 4.

r = 4

So the center is (0, 0) and the radius is 4.

center (0, 0) and r = 4

4 Check

Let's check: draw the circle.

Center (0, 0), radius 4.

Put the center on the grid.

Draw the circle around it.

Its right end is on the circle: (4, 0), 4 to the right of the center.

Put x = 4 and y = 0 in.

We get 4² + 0².

42 + 02 = 42 + 02

16 plus 0 is 16, the number on the right.

Right!

= 16 + 0 = 16

Let's look back.

First: compare with the rule.

Then: find the center.

Then: find the radius.

Last: check.

Answer
center (0, 0) and r = 4

Your turn

Try this one yourself, then check:

Find the center and the radius of x2 + y29
Show the answer
center (0, 0) and r = 3

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