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Center and radius of x^2 + y^2 + 8y = 0

Step by step, with the reason for every step · Circle from the general form · Geometry

Step by step

The question

Question: find the center and the radius of x² + y² + 8y = 0.

x2 + y2 + 8y = 0

1 Group x and y

Put the x terms together in a bracket, and the y terms together.

x2 + (y2 + 8y) = 0

2 Complete the square for y

To make y² + 8y a full square: half of 8 is 4.

4 times 4 is 16.

So we add 16.

We do it on both sides, so they stay equal.

x2 + (y2 + 8y + 16) = 0 + 16
8 ÷ 2 = 4, 4 × 4 = 16

Careful!

What we add on the left, we add on the right too.

Then the two sides stay equal.

Careful: add 16 on both sides

3 Write as squares

Each bracket is now a full square.

On the right, 0 + 16 is 16.

So x² + (y + 4)² = 16.

x2 + (y + 4)2 = 16

y² + 8y + 16 is (y + 4)².

y² + 8y + 16 = (y + 4)2

4 Read the center and radius

Compare with the circle rule: (x − h)² + (y − k)² = r².

(x − h)2 + (y − k)2 = r2

The signs turn: x² gives h = 0.

y + 4 gives k = −4.

y + 4 → k = −4
x → h = 0

So the center is (0, −4).

center = (0, −4)

r² is 16.

So r is the square root of 16: 4, because 4 times 4 is 16.

r = √16 = 4

So the center is (0, −4) and the radius is 4.

center (0, −4) and r = 4

5 Check

Let's check with a point on the circle: (4, −4), 4 to the right from the center.

Put it in the first equation.

4² + (−4)² + 8 × (−4) = 16 + 16 − 32 = 0

We get 0, the same as the right side.

So the center and the radius are right!

Let's look back.

First: group x and y.

Then: complete the square for y.

Then: write as squares.

Then: read the center and radius.

Last: check.

Answer
center (0, −4) and r = 4

Your turn

Try this one yourself, then check:

Find the center and the radius of x2 + y2 + 4y = 12
Show the answer
center (0, −2) and r = 4

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