Coordinates of (1, 1) in the basis (2, 1), (3, 2) Step by Step

Step by step

The question

Question: find the coordinates of (1, 1) in the basis (2, 1) and (3, 2).

b₁ = [2; 1], b₂ = [3; 2]

We call the basis vectors b₁ and b₂, in this order, and the vector v.

v = [1; 1]

The coordinates of v are the numbers that make v from the basis vectors, in the basis order.

coordinates: the numbers c₁, ..., c₂ in

v = c₁b₁ + c₂b₂

1 Write the vector equation

We look for c₁ and c₂.

c₁[2; 1] + c₂[3; 2] = [1; 1]

2 Write the augmented matrix

Each vector goes in as a column: the first entries make row 1, the second entries row 2.

v goes after the bar.

= [2, 3, 1; 1, 2, 1]

We call the rows R 1 and R 2.

3 Row reduce

We use the three row moves: swap two rows, times a row by a number that is not 0, add a multiple of one row to another.

They never change the answers.

Our goal: a leading 1 in each row, with 0s above and below it.

swap two rows

× a row by a number (not 0)

add a multiple of one row to another

→ [1, 2, 1; 2, 3, 1]

→ [1, 2, 1; 0, −1, −1]

→ [1, 2, 1; 0, 1, 1]

→ [1, 0, −1; 0, 1, 1]

4 Read the coordinates

Each row is an equation again.

Row 1: c₁ = −1.

c₁ = −1

Row 2: c₂ = 1.

c₂ = 1

We write them as a column, in the basis order: (−1, 1).

[v]_B = [−1; 1]

Careful!

The order follows the basis.

c₁ goes with b₁, so it comes first.

Careful: not (1, −1) ✗

5 Check

Let's check: −b₁ + b₂ must give v.

= −[2; 1] + [3; 2]

= [−2 + 3; −1 + 2]

= [1; 1]

We get (1, 1): that is v.

So the answer is right!

Let's look back.

First: write the vector equation.

Then: write the augmented matrix.

Then: row reduce.

Then: read the coordinates.

Last: check.

Answer