Steply

Critical points of f(x, y) = x^2 - y^2

Step by step, with the reason for every step · Local maximum, minimum and saddle points · Calculus 3

Step by step

The question

Question: find and classify the critical points of f(x, y) = x² − y².

f(x, y) = x2 − y2

1 Find the critical points

At a top, a bottom or a saddle, the surface is flat: both partial derivatives are 0.

Term by term.

x²: the power 2 comes down.

The power goes down by 1.

So 2x.

y² has no x: it is a fixed number, so it gives 0.

∂f∂x = 2x + 0

Drop the zeros: ∂f/∂x = 2x.

∂f∂x = 2x

Term by term.

x² has no y: it is a fixed number, so it gives 0.

y²: the power 2 comes down: −1 times 2 is −2.

The power goes down by 1.

So 2y.

∂f∂y = 0 − 2y

Drop the zeros: ∂f/∂y = −2y.

∂f∂y = −2y

Set ∂f/∂x = 0.

It has only x in it.

2x = 0

Divide by 2: x = 0.

x = 0

Set ∂f/∂y = 0.

It has only y in it.

−2y = 0

Divide by −2: y = 0.

y = 0

So there is one critical point: (0, 0).

= (0, 0)

2 The second partials

Term by term.

2x gives 2.

So f_xx = 2.

fxx = 2

Term by term.

2y gives 2.

So f_yy = −2.

fyy = −2

Term by term.

2x has no y: it is a fixed number, so it gives 0.

fxy = 0

Drop the zeros: f_xy = 0.

fxy = 0

The test number: D = f_xx × f_yy − (f_xy)².

D = fxx × fyy − (fxy)²

3 Test each point

At (0, 0): f_xx is 2, f_yy is −2, f_xy is 0.

So D is −4.

D(0, 0) = 2 × (−2) − 0² = −4

Careful!

f_xx alone is not enough.

If D is negative, it is a saddle, whatever f_xx is.

Careful: D first, then the sign of fxx

D is negative: up one way, down the other.

A saddle point.

(0, 0): = saddle point

4 Check

Let's check.

Here is the surface near (0, 0).

It is a saddle: up one way, down the other.

Now small steps away from the point.

Near (0, 0), one step gives a bigger value, the other a smaller one.

That fits a saddle point.

Right!

f(0, 0) = 0: f(0.1, 0) = 0.01, f(0, 0.1) = −0.01

Let's look back.

First: find the critical points.

Then: the second partials.

Then: test each point.

Last: check.

Answer
= (0, 0)

Your turn

Try this one yourself, then check:

Find and classify the critical points of f(x, y) = 4x2 − 3y2
Show the answer
saddle point at (0, 0)

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