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Cuboid 4 cm by 3 cm by 10 cm, angle between the diagonal and the base

Step by step, with the reason for every step · Trigonometry in 3D · Geometry

Step by step

The question

Question: a cuboid is 4 cm by 3 cm by 10 cm: find the angle between the diagonal A G and the base.

1 Find the right triangle

The line is the diagonal A G, from a bottom corner to the opposite top corner.

Its shadow on the base is A C: right under it, along the floor.

C G goes straight up from the base.

So A C G is a right triangle, with the right angle at C.

The angle between the line and the base is θ, at A, between A G and its shadow A C.

2 Base diagonal

A C is the diagonal of the bottom rectangle.

Pythagoras: 4 squared plus 3 squared is 25.

AC2 = 4² + 3² = 16 + 9 = 25

So A C is 5.

AC = 5

Careful!

Not the angle with the bottom edge.

The angle with the base is the angle with the shadow on the base.

Careful: the angle is with the shadow AC, not with an edge

3 The angle

θ is at A.

The side across from it goes up: 10.

The side next to it is the shadow, AC.

Tan is opposite over adjacent.

tan θ = 105
tan = opposite ÷ adjacent

To get the angle back, we use tan to the minus 1 on a calculator: about 63.4°, to the nearest tenth.

θ = tan⁻¹(105) ≈ 63.4°

4 Check

Let's check another way.

The whole line AG is the square root of 25 plus 100.

Sin θ is 10 over that.

Sin to the minus 1 gives 63.4° again.

So it is right!

AG = √(25 + 100) = √125, sin⁻¹(10 ÷ √125) ≈ 63.4°

Let's look back.

First: find the right triangle.

Then: base diagonal.

Then: the angle.

Last: check.

Answer
θ = tan⁻¹(105) ≈ 63.4°

Your turn

Try this one yourself, then check:

Find the angle θ.
Show the answer
θ ≈ 70.2°

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