Steply

Cuboid 5 by 12 by 13, angle between the diagonal and the base

Step by step, with the reason for every step · Trigonometry in 3D · Geometry

Step by step

The question

Question: a cuboid is 5 by 12 by 13: find the angle between the diagonal A G and the base.

1 Find the right triangle

The line is the diagonal A G, from a bottom corner to the opposite top corner.

Its shadow on the base is A C: right under it, along the floor.

C G goes straight up from the base.

So A C G is a right triangle, with the right angle at C.

The angle between the line and the base is θ, at A, between A G and its shadow A C.

2 Base diagonal

A C is the diagonal of the bottom rectangle.

Pythagoras: 5 squared plus 12 squared is 169.

AC2 = 5² + 12² = 25 + 144 = 169

So A C is 13.

AC = 13

Careful!

Not the angle with the bottom edge.

The angle with the base is the angle with the shadow on the base.

Careful: the angle is with the shadow AC, not with an edge

3 The angle

θ is at A.

The side across from it goes up: 13.

The side next to it is the shadow, AC.

Tan is opposite over adjacent.

tan θ = 1313
tan = opposite ÷ adjacent

To get the angle back, we use tan to the minus 1 on a calculator: about 45.0°, to the nearest tenth.

θ = tan⁻¹(1313) ≈ 45.0°

4 Check

Let's check another way.

The whole line AG is the square root of 169 plus 169.

Sin θ is 13 over that.

Sin to the minus 1 gives 45.0° again.

So it is right!

AG = √(169 + 169) = √338, sin⁻¹(13 ÷ √338) ≈ 45.0°

Let's look back.

First: find the right triangle.

Then: base diagonal.

Then: the angle.

Last: check.

Answer
θ = tan⁻¹(1313) ≈ 45.0°

Your turn

Try this one yourself, then check:

Find the angle θ.
Show the answer
θ ≈ 58.2°

More from Trigonometry in 3D

The whole lesson: Trigonometry in 3D →