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Derivative of sin^-1(3x)

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find the derivative of f(x) = sin⁻¹(3x).

f(x) = sin⁻¹(3x)

1 The rule

The rule: the derivative of sin⁻¹ u is 1 over √(1 − u²).

sin⁻¹ u → 1√1 − u²

2 The inside

There is something inside: 3x.

Call it u.

u = 3x

3 The outside

First the outside: the rule on sin⁻¹ u.

dydu = 1√1 − u²

4 The inside's slope

The inside's slope: the power rule on 3x gives 3.

dudx = 3

5 Multiply

The chain rule: multiply the two, and put 3x back in place of u.

f′(x) = 1√1 − (3x)2 × 3

Careful!

Do not stop at the outside.

Multiply by the inside's slope, 3.

Careful: not 1√1 − (3x)2 ✗

Square the inside: (3x)² is 9x².

(3x)2 = 9x2

Tidy up: f′(x) = 3 over √(1 − 9x²).

= 3√1 − 9x2

6 Check

Let's check: the derivative is the slope.

At x = 0.2, our answer gives 3.75, with a calculator in radians.

f′(0.2) = 3.75

Now the slope between two very close points: x = 0.2 and x = 0.201.

A calculator gives about 3.76.

Very close to 3.75.

Right!

f(0.201) − f(0.2)0.001 ≈ 3.76

Let's look back.

First: the rule.

Then: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 3√1 − 9x2

Your turn

Try this one yourself, then check:

f(x) = sin⁻¹(2x)
Show the answer
f′(x) = 2√1 − 4x2

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