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Derivative of sin^-1(x^2)

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find the derivative of f(x) = sin⁻¹(x²).

f(x) = sin⁻¹(x2)

1 The rule

The rule: the derivative of sin⁻¹ u is 1 over √(1 − u²).

sin⁻¹ u → 1√1 − u²

2 The inside

There is something inside: x².

Call it u.

u = x2

3 The outside

First the outside: the rule on sin⁻¹ u.

dydu = 1√1 − u²

4 The inside's slope

The inside's slope: the power rule on x² gives 2x.

dudx = 2x

5 Multiply

The chain rule: multiply the two, and put x² back in place of u.

f′(x) = 1√1 − (x2)2 × 2x

Careful!

Do not stop at the outside.

Multiply by the inside's slope, 2x.

Careful: not 1√1 − (x2)2 ✗

Square the inside: (x²)² is x⁴.

(x2)2 = x4

Tidy up: f′(x) = 2x over √(1 − x⁴).

= 2x√1 − x4

6 Check

Let's check: the derivative is the slope.

At x = 0.5, our answer gives 1.0328, with a calculator in radians.

f′(0.5) = 1.0328

Now the slope between two very close points: x = 0.5 and x = 0.501.

A calculator gives about 1.03.

Very close to 1.0328.

Right!

f(0.501) − f(0.5)0.001 ≈ 1.03

Let's look back.

First: the rule.

Then: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 2x√1 − x4

Your turn

Try this one yourself, then check:

f(x) = sin⁻¹(3x2)
Show the answer
f′(x) = 6x√1 − 9x4

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