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Derivative of tan^-1(x^3)

Step by step, with the reason for every step · Derivatives of inverse trig functions · Calculus 1

Step by step

The question

Question: find the derivative of f(x) = tan⁻¹(x³).

f(x) = tan⁻¹(x3)

1 The rule

The rule: the derivative of tan⁻¹ u is 1/(1 + u²).

tan⁻¹ u → 11 + u²

2 The inside

There is something inside: x³.

Call it u.

u = x3

3 The outside

First the outside: the rule on tan⁻¹ u.

dydu = 11 + u²

4 The inside's slope

The inside's slope: the power rule on x³ gives 3x².

dudx = 3x2

5 Multiply

The chain rule: multiply the two, and put x³ back in place of u.

f′(x) = 11 + (x3)2 × 3x2

Careful!

Do not stop at the outside.

Multiply by the inside's slope, 3x².

Careful: not 11 + (x3)2 ✗

Square the inside: (x³)² is x⁶.

(x3)2 = x6

Tidy up: f′(x) = 3x² over (1 + x⁶).

= 3x21 + x6

6 Check

Let's check: the derivative is the slope.

At x = 1, our answer gives 1.5, with a calculator in radians.

f′(1) = 1.5

Now the slope between two very close points: x = 1 and x = 1.001.

A calculator gives about 1.5.

Very close to 1.5.

Right!

f(1.001) − f(1)0.001 ≈ 1.5

Let's look back.

First: the rule.

Then: the inside.

Then: the outside.

Then: the inside's slope.

Then: multiply.

Last: check.

Answer
= 3x21 + x6

Your turn

Try this one yourself, then check:

f(x) = tan⁻¹(3x3)
Show the answer
f′(x) = 9x21 + 9x6

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