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Derivative of (x^3 + 1)(2x - 1)

Step by step, with the reason for every step · Product and quotient rules · Calculus

Step by step

The question

Question: find the derivative of f(x) = (x³ + 1)(2x − 1).

f(x) = (x3 + 1)(2x − 1)

1 Name u and v

Call the first bracket u: x³ + 1.

u = x3 + 1

Call the second bracket v: 2x − 1.

v = 2x − 1

2 Find u′ and v′

The power rule on u gives u′ = 3 x².

u′ = 3x2

On v it gives v′ = 2.

v′ = 2

3 Use the rule

The product rule: the derivative of u times v is u′ v plus u v′.

(uv)′ = u′v + uv′

Put them in.

f′(x) = (3x2)(2x − 1) + (x3 + 1)(2)

Careful!

Not u′ times v′!

Each part needs the other bracket.

Careful: not u′ × v′ = 6 x² ✗

4 Open the brackets

What is in front of a bracket multiplies every part inside.

= 6x3 − 3x2 + 2x3 + 2

Terms are the parts between the + and − signs.

Like terms are the same kind: same letters, same powers.

All the x terms go together.

Plain numbers go together.

So f′(x) = 8 x³ − 3 x² + 2.

= 8x3 − 3x2 + 2

5 Check

Let's check another way: multiply the brackets out first.

f(x) is 2 x⁴ − x³ + 2x − 1.

f(x) = 2x4 − x3 + 2x − 1

The power rule on that gives 8 x³ − 3 x² + 2.

The same!

Right!

f′(x) = 8x3 − 3x2 + 2

Let's look back.

First: name u and v.

Then: find u′ and v′.

Then: use the rule.

Then: open the brackets.

Last: check.

Answer
= 8x3 − 3x2 + 2

Your turn

Try this one yourself, then check:

Find the derivative of f(x) = (x3 + 1)(4x − 2)
Show the answer
f′(x) = 16x3 − 6x2 + 4

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